Answer:
P = 2 pi R / v period of space station
F / m = v^2 / R centripetal force per unit of mass
So F / m = 4 pi^2 R^2 / (P^2 * R) = 4 pi^2 R / P^2
Also, F / m = 9.8 m/s^2 earth's gravitational attraction
So 9.8 = 4 pi^2 R / P^2 or R = 9.8 P^2 / 4 * pi^2) = 195 m
Or D = 2 R = 390 m the diameter required
Answer:
A.)
Explanation:
Because you didn't add anything or take anything away.
Answer:
Explanation:
False --> A cylindrical capacitor is essentially a parallel plate capacitor rolled into a tube. This is because a cylindrical capacitor comprises two cylinders.
False --> The dielectric constant indicates the distance by which the two plates of a capacitor are separated.
True --> The charge on a capacitor increases quickly at first, then much more slowly as the capacitor charges. This is because the charge on the capacitor increases exponentially.
False --> The voltage across a capacitor in an RC circuit increases linearly during charging. This is because the voltage increases exponentially.
True --> One of the principal purposes of a capacitor is to store electric potential energy.
True --> A capacitor charges rapidly when connected to an RC circuit with a battery. This is because a cylindrical capacitor is basically a parallel plate capacitor rolled into a tube.
Answer:
50,000 V/m
Explanation:
The electric field between two charged metal plates is uniform.
The relationship between potential difference and electric field strength for a uniform field is given by the equation
where
is the potential difference
E is the magnitude of the electric field
d is the distance between the plates
In this problem, we have:
is the potential difference between the plates
d = 15 mm = 0.015 m is the distance between the plates
Therefore, rearranging the equation we find the strength of the electric field:
Answer:
Frquency=3,994Hz
Explanation:
Tension =967N
Density of string (μ)=0.023g/cm
Length of the stretched spring=308cm
Fundamental frequency for nth harmonic :
Fn=n/2L(√T/μ)
Substituting the given values to find the frequency :
f1=1/2(308cm) *(0.01m/1cm)[(√967N)/(0.023g/cm)(0.1kg)/(0.1kg/m)/(1g/cm)]
=6.16m[(√967N)/0.0023kg/m)]
=3,994.20Hz
Approximately,
The frequency will be =3,994Hz
