Because upward buoyant force is slightly higher than gravitation force for this particular object
Answer:
I'm not completely sure, but I believe the first and third of the three are mechanical.
Explanation:
Chemical potential isn't moving or about to go into motion. It can't be mechanical.
Answer:
0.893 rad/s in the clockwise direction
Explanation:
From the law of conservation of angular momentum,
angular momentum before impact = angular momentum after impact
L₁ = L₂
L₁ = angular momentum of bullet = + 9 kgm²/s (it is positive since the bullet tends to rotate in a clockwise direction from left to right)
L₂ = angular momentum of cylinder and angular momentum of bullet after collision.
L₂ = (I₁ + I₂)ω where I₁ = rotational inertia of cylinder = 1/2MR² where M = mass of cylinder = 5 kg and R = radius of cylinder = 2 m, I₂ = rotational inertia of bullet about axis of cylinder after collision = mR² where m = mass of bullet = 0.02 kg and R = radius of cylinder = 2m and ω = angular velocity of system after collision
So,
L₁ = L₂
L₁ = (I₁ + I₂)ω
ω = L₁/(I₁ + I₂)
ω = L₁/(1/2MR² + mR²)
ω = L₁/(1/2M + m)R²
substituting the values of the variables into the equation, we have
ω = L₁/(1/2M + m)R²
ω = + 9 kgm²/s/(1/2 × 5 kg + 0.02 kg)(2 m)²
ω = + 9 kgm²/s/(2.5 kg + 0.02 kg)(4 m²)
ω = + 9 kgm²/s/(2.52 kg)(4 m²)
ω = +9 kgm²/s/10.08 kgm²
ω = + 0.893 rad/s
The angular velocity of the cylinder bullet system is 0.893 rad/s in the clockwise direction-since it is positive.
Answer:
Her acceleration is 0 m/s²
Explanation:
We note that the motion of the girl is on a straight road, therefore;
The vertical acceleration (e.g. due to gravity, <em>g)</em> on the horizontal motion = 0
The horizontal acceleration, a = (Change in velocity, Δv)/(Change in time, Δt)
For uniform velocity, the change in velocity, Δv = 0
Therefore, fore any change in time, Δt, we have;
a = Δv/Δt
Her acceleration, a = 0/Δt = 0
Her acceleration, a = 0 m/s²
Nearly 14 billion years, according to astronomers. Happy to help!
