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Nostrana [21]
2 years ago
6

. How many grams of Na2SO4 are required to make 2700 mL of a 2.0 M solution?

Chemistry
2 answers:
ratelena [41]2 years ago
6 0

Answer:

Explanation:

From the net ionic equation

Ba2+(aq) + SO42-(aq) ==> BaSO4(s) we see that 1 mole Ba2+ reacts with 1 mole SO42- to -> 1 mol BaSO4

Find moles of Ba2+ used: 0.250 moles/L x 0.0323 L = 0.008075 moles Ba2+

Find moles SO42- present: 0.008075 moles Ba2+ x 1 mol SO42-/1 mol Ba2+ = 0.008075 mol SO42-

Find mass of Na2SO4 present: 0.008075 mol SO42- x 1 mol Na2SO4/1 mol SO42- x 142.04 Na2SO4/mole = 1.14698 g = 1.15 g Na2SO4 (to 3 significant figures)

Andru [333]2 years ago
6 0

Answer: Approx 2kg of salt are required.

Explanation: If 4.5 ⋅ L of a 3.0 ⋅ m o l ⋅ L − 1 solution are required, this is a molar quantity of 4.5 ⋅ L × 3.0 ⋅ m o l ⋅ L − 1 = 13.5 ⋅ m o l . Now, we simply multiply this molar quantity by a molar mass to get the mass: 13.5 ⋅ m o l × 142.04 ⋅ g ⋅ m o l − 1 = ? ? ⋅ g

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Number of moles in 31.99g O2 <br> And 176.8g NaCl
sergey [27]

#O_2

\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}

\\ \sf\longmapsto No\:of\:moles=\dfrac{31.99}{32}

\\ \sf\longmapsto No\:of\:moles\approx 1

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\\ \sf\longmapsto No\:of\:moles=\dfrac{176.8}{58.5}

\\ \sf\longmapsto No\;of\:moles=3mol

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timurjin [86]

Answer: fourth option, 10.8 kJ


Explanation:


The <em>heat of fusion</em>, also named latent heat of fusion, is the amount of heat energy required to change the state of a substance from solid to liquid (at constant pressure).


The data of the <em>heat of fusions</em> of the substances are reported in tables and they can be shown either per mole or per gram of substance.


In this case we have that the<em> heat of fusion for water </em>is reported per mole: <em>6.02 kJ/mole</em>.


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The calculations are:

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        number of moles = 32.3 g / 18.015 g/mol = 1.79 mol

       

  • Heat = 1.79 mol × 6.02 kJ / mol = 10.8 kJ ← answer
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(2 x 109) x (5 x 105).
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Answer:

114450

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