Answer: The given reaction is a double displacement reaction.
Explanation:
A chemical reaction equation in which both positive and negative ions of two different reactants are exchanged then it is called a double displacement reaction.
For example, ![Na_{2}SO_{4} + H_{2}O \rightarrow H_{2}SO_{4} + Na_{2}O](https://tex.z-dn.net/?f=Na_%7B2%7DSO_%7B4%7D%20%2B%20H_%7B2%7DO%20%5Crightarrow%20H_%7B2%7DSO_%7B4%7D%20%2B%20Na_%7B2%7DO)
Here, hydrogen ions of
are replaced by the sodium ions of
. Also, sulfate ion of
are replaced by oxygen ion of
.
Thus, we can conclude that the given reaction is a double displacement reaction.
Answer:
7.58
Explanation:
Given that
A buffer solution obtained by dissolving 13.0 g of KH₂PO₄ and 26.0 g of Na₂HPO₄ in water and then diluting to 1.00 L.
pKa = 7.21.
To get the PH we are going to use Henderson - Hasselblach equation:
PH = Pka + ㏒ [A/AH]
when the molar mass of Na2HPO4 = 142 g/mol
and A is the conjugate base HPO4-- ions so,
∴[A] = 32g / 142 g/mol
= 0.225 M
and when the molar mass of KH2PO4 = 136 g/mol
and AH is the weak acid H2PO4- ions so,
∴[AH] = 13 g / 136 g/mol
= 0.096 M
and when we have the Pka value of H3PO4 = 7.21
so, by substitution:
∴ PH = 7.21 + ㏒ (0.225 / 0.096)
= 7.58
Answer:
PH. PH2. PH3.
Explanation:
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Answer:
im pretty sure its 2.7 gms
Explanation:
im not for sure tho