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S_A_V [24]
2 years ago
5

You open the refrigerator and take out a slice of leftover pizza. You put it in the microwave oven, turn it on, and watch for th

e cheese to start bubbling. You take a bite of the pizza and realize it is too hot, so you let it sit on the counter for a minute. When the pizza is finally cool enough to eat, you enjoy your lunch. Identify three examples of energy transfer in the scenario.
Pick up to 3 answers.
A. Electromagnetic (microwave) energy is transferred from the refrigerator to the pizza in the refrigerator.
B. Electromagnetic (microwave) energy is transferred from the microwave to the pizza in the microwave oven.
C. Heat energy is transferred from the pizza to the room as the pizza cools on the counter.
D. Heat energy from the warm pizza is transferred from the pizza into the mouth chewing it.
E. Heat energy from the room is transferred into the pizza as it comes out of the microwave oven.
Chemistry
1 answer:
Vesnalui [34]2 years ago
7 0

Answer:

C,B,(D or A)

Explanation:

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Under what conditions can calcium bromide conduct electricity
Marat540 [252]
CaBr conducts electricity in the molten state but does not conduct as a solid. ionic dissolution equation.
7 0
2 years ago
True or false if an object displaces 50 ml of water the object's volume is 50mL
andrew11 [14]

Answer:

True

Explanation:

The volume of water displaced by an object completely submerged is its actual volume. It implies that in the container the object create a space of size for itself which is the volume of the object. This approach is used in calculating the density of many irregular solids from their measured masses.

6 0
3 years ago
How much heat is gained when a 50.32g piece of aluminum is heated from 9.0°c to 16°c
Rashid [163]

Answer: 317 joules

Explanation:

The quantity of heat energy (Q) gained by aluminium depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

In this case,

Q = ?

Mass of aluminium = 50.32g

C = 0.90J/g°C

Φ = (Final temperature - Initial temperature)

= 16°C - 9°C = 7°C

Then, Q = MCΦ

Q = 50.32g x 0.90J/g°C x 7°C

Q = 317 joules

Thus, 317 joules of heat is gained.

5 0
3 years ago
Read 2 more answers
Elle wanted to test how temperature affects the rate of evaporation. She had three setups:
Pie

Answer:

Temperature

Explanation:

Here the factor that Elle is controlling is the temperature. So temperature here is the independent variable and the dependent variable is the rate of evaporation of water.  Independent variable is controlled during the experiment setup and the outcome of the dependent variable depends on the independent variable.

5 0
3 years ago
"Compounds A and B react to give a single product, C. Write the rate law for each of the following cases and determine the units
olasank [31]

Answer:

Part a: <em>Units of k is </em>M^{-2}s^{-1}<em> where reaction is first order in A and second order in B</em>

Part b: <em>Units of k is </em>M^{-1}s^{-1}<em> where reaction is first order in A and second order overall.</em>

Part c: <em>Units of k is </em>M^{-1}s^{-1}<em> where reaction is independent of the concentration of A and second order overall.</em>

Part d: <em>Units of k is </em>M^{-3}s^{-1}<em> where reaction reaction is second order in both A and B.</em>

Explanation:

As the reaction is given as

A+B \rightarrow C

where as the rate is given as

r=k[A]^x[B]^y

where x is the order wrt A and y is the order wrt B.

Part a:

x=1 and y=2 now the reaction rate equation is given as

r=k[A]^1[B]^2

Now the units are given as

r=k[A]^1[B]^2\\M/s =k[M]^1[M]^2\\M/s =k[M]^{1+2}\\M/s =k[M]^{3}\\M^{1-3}/s =k\\M^{-2}s^{-1} =k

The units of k is M^{-2}s^{-1}

Part b:

x=1 and o=2

x+y=o

1+y=2

y=2-1

y=1

Now the reaction rate equation is given as

r=k[A]^1[B]^1

Now the units are given as

r=k[A]^1[B]^1\\M/s =k[M]^1[M]^1\\M/s =k[M]^{1+1}\\M/s =k[M]^{2}\\M^{1-2}/s =k\\M^{-1}s^{-1} =k

The units of k is M^{-1}s^{-1}

Part c:

x=0 and o=2

x+y=o

0+y=2

y=2

y=2

Now the reaction rate equation is given as

r=k[A]^0[B]^2

Now the units are given as

r=k[B]^2\\M/s =k[M]^2\\M/s =k[M]^{2}\\M^{1-2}/s =k\\M^{-1}s^{-1} =k

The units of k is M^{-1}s^{-1}

Part d:

x=2 and y=2

Now the reaction rate equation is given as

r=k[A]^2[B]^2

Now the units are given as

r=k[A]^2[B]^2\\M/s =k[M]^2[M]^2\\M/s =k[M]^{2+2}\\M/s =k[M]^{4}\\M^{1-4}/s =k\\M^{-3}s^{-1} =k

The units of k is M^{-3}s^{-1}

7 0
3 years ago
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