Answer:
option A is the correct answer .
Explanation:
as density = mass per unit volume
density = 7.5/2.5 = 3 gm / cm³ ..is the answer ...
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The answer is B. Below freezing
Answer:
142.82 g
Explanation:
The following data were obtained from the question:
Volume of water = 12 mL
Volume of water + gold = 19.4 mL
Density of gol= 19.3 g/cm³
Mass of gold =.?
Next, we shall determine the volume of the gold. This can be obtained as follow:
Volume of water = 12 mL
Volume of water + gold = 19.4 mL
Volume of gold =.?
Volume of gold = (Volume of water + gold) – (Volume of water)
Volume of gold = 19.4 – 12
Volume of gold = 7.4 mL
Finally, we shall determine the mass of the gold as follow:
Note: 1 mL is equivalent to 1 cm³
Volume of gold = 7.4 mL
Density of gol= 19.3 g/cm³ = 19.3 g/mL
Mass of gold =?
Density = mass /volume
19.3 = mass of gold /7.4
Cross multiply
Mass of gold = 19.3 × 7.4
Mass of gold = 142.82 g
Therefore, the mass of the gold pebble is 142.82 g
1) Magnesium Chloride
2) Sodium Bromide
3) Magnesium Oxide
4) Nickel (III) Fluoride
5) Aluminum Chloride
6) <span>Rubidium Sulfide
7) Gallium Nitride
8) Calcium Sulfide
9) </span><span>Lead (IV) Oxide
10) </span><span>Cobalt (II) Oxide
</span>11) B<span>eryllium Sulfide
12) </span><span>Cesium Nitride</span>
