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slavikrds [6]
3 years ago
13

Which of the water softener​

Chemistry
1 answer:
WARRIOR [948]3 years ago
8 0

Answer:

GAS

Explanation:

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En la reacción I2(g) + Br2(g) « 2 IBr(g), Keq = 280 a 150°C. Suponga que se permite que 0.500 mol de IBr en un matraz de 1.00 L
love history [14]

Answer:

P IBr: 15.454atm

I₂: 0.923 atm

P Br₂: 0.923atm

Explanation:

Basados en la reacción:

I₂(g) + Br₂(g) ⇄ 2 IBr(g)

La constante de equilibrio, Keq, es definida como:

Keq = \frac{P_{IBr}^2}{P_{I_2}P_{Br_2}}

<em>Se cumple la relación de Keq = 280 cuando las presiones están en equilibrio</em>

Usando PV = nRT, la presión inicial de IBr es:

P = nRT / V; 0.500mol*0.082atmL/molK*423.15K / 1.00L = <em>17.3 atm</em>

<em />

Siendo las presiones en equilibrio:

P IBr: 17.3 - 2X

P I₂: X

P Br₂: X

<em>Donde X representa el avance de reacción.</em>

Remplazando en Keq:

280 = (17.3 - 2X)² / X²

280X² = 4X² - 69.2X + 299.29

0 = -276X² - 69.2X + 299.29

<em>Resolviendo para X:</em>

X = -1.174 → Solución falsa. No existen presiones negativas

X = 0.923 → Solución real

Así, las presiones parciales en equilibrio de cada compuesto son:

P IBr: 17.3 - 2X = <em>15.454atm</em>

P I₂: X =<em> 0.923atm</em>

P Br₂: X = <em>0.923atm</em>

3 0
3 years ago
Read 2 more answers
A 72.0-gram piece of metal at 96.0 °C is placed in 130.0 g of water in a calorimeter at 25.5 °C. The final temperature in the ca
tekilochka [14]

Answer: The answer is S = 0.1528 cal/g °C

Explanation:

By the law of conservation of energy, energy is neither created nor destroyed.

So, energy lost by metal pieces is equal to the energy gained by water in the calorimeter.

Specific heat of water is 1 cal/g °C

⇒ heat energy  Q = mSΔT, where m = mass of a substance

                                                        S = specific heat

                                                        ΔT = change in temperature

Now, the heat lost by metal piece, Q = 72×S×(96-31)

                                                      = 4680×S cal

Heat gained by water, Q = 130×1×(31-25.5)

                                        = 715 cal

⇒ 4680×S = 715.

⇒ S = 0.1528 cal/g °C.

6 0
3 years ago
CHEMISTRY MCQ HELP NEEDED, THANKS!
leonid [27]
D odours
Thats the answer please mark me as brainiest

7 0
3 years ago
Read 2 more answers
Which types of reactions would result in the formation of precipitate?
IRINA_888 [86]

Answer:

Double Displacement Reaction

Explanation:

A double displacement reaction is a type of chemical reaction in which the reactant ions exchange places to form new products. Usually, a double displacement reaction results in precipitate formation.

8 0
3 years ago
A solution is prepared by dissolving 8.75 grams of sodium chloride in enough volume of water to produce 112.0 grams of the NaCl
ICE Princess25 [194]

Answer : The percent by mass of the solution is 7.81 %

Explanation : Given,

Mass of NaCl = 8.75 g

Mass of solution = 112.0 g

Now we have to determine the percent by mass of the solution.

\text{Mass percent}=\frac{\text{Mass of NaCl}}{\text{Mass of solution}}\times 100

Putting values in above equation, we get:

\text{Mass percent}=\frac{8.75g}{112.0g}\times 100=7.81\%

Therefore, the percent by mass of the solution is 7.81 %

6 0
3 years ago
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