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Vikki [24]
4 years ago
15

A person struggles very hard to lift a large boulder. He puts in so much effort, he starts to sweat, his heart rate increases, a

nd he gets really tired. All of his effort is for nothing, the boulder does not move at all. In this situation, has work been done? Explain!
*Use the scientific definition of "work" to answer this question.
Chemistry
1 answer:
Tems11 [23]4 years ago
6 0
No, according to physics no work has been done.

Work must have been done by muscular force but in terms of physics no work has been done.

In physics,work is said to be done only if the force applied produced some kind of displacement in the direction of force.

In this example provided, no work has been done since the boulder doesn't get displaced,it continues to remain at its original position.

Hope This Helps You!
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Can some right a paragraph about photosynthesis pls =))))))))))))))))))))))
Alina [70]

Answer:

Photosynthesis is the process in which plants harness energy from the sun to make their own nutrition. The process converts light energy into chemical energy through cellular respiration.

Explanation:

Just to start you off. I hope it helps! (❛ ᴗ ❛)

3 0
3 years ago
Read 2 more answers
Consider the following reaction and situations 1 through 10. In the spaces provided, clearly indicate the best response to each
olchik [2.2K]

Answer:

1. C. no change

2. A. increase

3. E. shift to the right

4. A. increase

5. E. shift to the right

6. A. increase

7. F. cannot be determined

8. B increase

9. D. shift to the left

10 F. cannot be determined

Explanation:

<em>According to Le Chaterlier principle, when a reaction is in equilibrium and one of the constraints that affect reactions is applied, the equilibrium will shift so as annul the effects of the constraints.</em>

From the equation: C(s) + H2O(g) ⇌ CO(g) + H2(g),

H is greater than 0, meaning that the system is endothermic, that is energy is absorbed.

1. If the pressure of the system is increased, there would be no change to the system because there are equal number of moles of products and reactants.

2. If H2 concentration is decreased, the equilibrium will shift to the right and more products will be formed. Hence, the concentration of CO will increase.

3. If H2 concentration is decreased, the equilibrium will shift to the right to annul the effects of the decrease in the concentration of a product.

4. If the concentration of H2 is increased, the equilibrium will shift to the left to annul the effects of increased concentration of a product. Hence, more H2O would be formed.

5. If H2 (a product) is removed, and C (a reactant) is added, more of the products will be formed in order to annul the effects of the actions. Hence, equilibrium will shift to the right.

6. If the amount of C (a reactant) is increased, the equilibrium will shift to the right. Hence, more H2 will be formed.

7. The reaction is endothermic, hence an increase in temperature will ordinarily shift the equilibrium to the right. However, the addition of H2 (a product) is supposed to shift the equilibrium to the left. Hence, the effects of simultaneous addition of the two actions become indeterminate.

8. Since the reaction is endothermic, increase in the temperature of the system will shift the equilibrium to the right. Hence, more CO will be formed.

9. If the concentration of H2O (a reactant) is decreased and that of CO (a product) is increased, both actions lead to the equilibrium being shifted to the left.

10. Addition of catalyst to the system will only speed up the rate at which the system reach the equilibrium.

5 0
3 years ago
Which of the following releases the greatest amount of energy as it proceeds? Assume the same mass of starting material is used
Ivanshal [37]
The answer should be <span>C. nuclear reaction.</span>
4 0
3 years ago
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likoan [24]
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6 0
3 years ago
Draw the structure of the starting material in the ozonolysis reaction below. Hint: The starting material and product have the s
Crank
<h3>Answer:</h3>

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<h3>Explanation:</h3>

                       Ozone is one of the reactive allotrope of oxygen. It reacts vigorously with unsaturated compounds like alkenes and alkynes. In this reaction alkene and O₃ first react to produce Molozonide which is highly unstable and rearranges to form a stable ozonide as shown in scheme attached below.

                      Furthermore, the ozonide on reduction is convertwed into ketones and aldehydes respectively.

6 0
4 years ago
Read 2 more answers
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