Answer:
See explanation below
Explanation:
In order to do this, you are missing two important data, which are the initial temperatures of the water and the rod.
For practical purposes, I will assume this data, and then you'll just replace the procedure with your data to get an accurate result.
So, for this exercise, I will assume that the rod of Chromiun was heat to 100 °C and then cooled with water at 20 °C, so the final temperature is 54.5 °C.
To get the specific heat, we need to use the following expression:
q = m.C.ΔT (1)
Where:
q: Heat of the substance/compound
m: mass
C: specific heat
ΔT: Difference of temperature of the mixture.
With this expression, we need to calculate first the heat of the water, because:
q₁ + q₂ = 0
Therefore, with the value of the transfered heat, we can determine later the specific heat. So, As we have the specific heat of water which is 4.18 J/g °C, and the temperature and mass, we can determine the heat of the mixture:
ΔT = 54.5 - 20 = 34.5 °C
q₁ = 35 * 4.18 * 34.5
q₁ = 5047.35 J
Now, we can determine the specific heat of the rod:
q₁ = -q₂
-5047.35 = 323.98 * (54.5 - 100) * C
-5047.35 = -14741.09C
<h2>
C = 0.34 J/g °C</h2>
Hope this helps
