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3 years ago

How are magnetic poles and electrical charges similar?

Physics

2 answers:

pshichka [43]3 years ago

7 0

Answer: The correct answer is "Their same forces repel each other, and their opposite forces attract each other".

Explanation:

Magnet has two poles: South pole and North pole.

There is magnetic force of repulsion between the same poles as the same poles repel each other. There is magnetic force of attraction between the opposite poles as the opposite poles attract each other.

The charges can be negative and positive.

There is electrostatic force of repulsion between the same charges as the same charges repel each other. There is electrostatic force of attraction between the opposite charges as the opposite charges attract each other.

Therefore, the correct option is (A).

exis [7]3 years ago

3 0

I believe the answer is a

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When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racq

Lilit [14]

Answer:60 gm

Explanation:

Given

initial velocity of ball $u=0$

Force exerted by racquet $F=540 N$

time period of force $t=5\ ms$

final velocity of ball $v=45\ m/s$

Racquet imparts an impulse to the ball which is given by

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3 years ago

Which of the following is not an example of a molecule? A.H2O2 B.NCl3 C.F D.O3

lara [203]

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3 years ago

Read 2 more answers

An ice sled powered by a rocket engine starts from rest on a large frozen lake and accelerates at +44 ft/s2. After some time t1,

mash [69]

Answer:

a) t₁ = 4.76 s, t₂ = 85.2 s

b) v = 209 ft/s

Explanation:

Constant acceleration equations:

x = x₀ + v₀ t + ½ at²

v = at + v₀

where x is final position,

x₀ is initial position,

v₀ is initial velocity,

a is acceleration,

and t is time.

When the engine is on and the sled is accelerating:

x₀ = 0 ft

v₀ = 0 ft/s

a = 44 ft/s²

t = t₁

So:

x = 22 t₁²

v = 44 t₁

When the engine is off and the sled is coasting:

x = 18350 ft

x₀ = 22 t₁²

v₀ = 44 t₁

a = 0 ft/s²

t = t₂

So:

18350 = 22 t₁² + (44 t₁) t₂

Given that t₁ + t₂ = 90:

18350 = 22 t₁² + (44 t₁) (90 − t₁)

Now we can solve for t₁:

18350 = 22 t₁² + 3960 t₁ − 44 t₁²

18350 = 3960 t₁ − 22 t₁²

9175 = 1980 t₁ − 11 t₁²

11 t₁² − 1980 t₁ + 9175 = 0

Using quadratic formula:

t₁ = [ 1980 ± √(1980² - 4(11)(9175)) ] / 22

t₁ = 4.76, 175

Since t₁ can't be greater than 90, t₁ = 4.76 s.

Therefore, t₂ = 85.2 s.

And v = 44 t₁ = 209 ft/s.

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3 years ago

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vaieri [72.5K]

Answer:

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3 years ago

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dmitriy555 [2]

Answer:

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Explanation:

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