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4 years ago

6

Match each phrase to the form of energy it represents. Tiles chemical potential energy electric energy vibrational energy motion

energy electric potential energy radiant energy Pairs fuel in a car's gas tank flash of lightning storm clouds vocalist singing

2 answers:

alex41 [277]4 years ago

5 0

<span><span>fuel in a car's gas tank- Chemical Potential Energy</span><span>flash of lightning- Radiant Energy </span><span>storm clouds- Electric Energy</span><span>vocalist singing- Vibrational Energy </span><span>recording sound with a microphone- Electric Potential Energy</span><span>raindrops falling- Motion Energy
HOPE THIS HELPED :)
</span></span>

finlep [7]4 years ago

3 0

fuel in a car's gas tank- Chemical Potential Energy

flash of lightning- Radiant Energy

Storm clouds- Electric Energy

vocalist singing- Vibrational Energy

recording sound with a microphone- Electric Potential Energy

raindrops falling- Motion Energy

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Imagine you had a bar of gold and decided to cut in half. You repeated this process until eventually you could no longer cut the

nydimaria [60]

This would prove that gold is an <em>element</em>. No matter how far down you
examine it, you never find any particles of anything except gold.

An example of a different case is salt.
-- Imagine you had a block of salt and decided to cut it in half.
-- If you repeated this process, then eventually, at some point, you'd have
a tiny particle of salt in front of you, just like before. BUT ...
-- Just as you were getting ready to cut this one in half, you'd notice that this
particle of salt is different. It's one atom of sodium stuck to one atom of chlorine,
and if you cut it in half, you would not have ANY salt. <span />

This would prove that salt is a <em><u>compound</u></em>, made of atoms of two or more elements.

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4 years ago

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In the process of changing a flat tire, a motorist uses a hydraulic jack. She begins by applying a force of 58 N to the input pi

AfilCa [17]

Answer:

The correct answer is "3899.92 N".

Explanation:

The given values are:

Force,

$F_{app}=58 N$

Ratio,

$\frac{R_2}{R_1}=8.2$

As we know,

Area, $A=\pi r^2$

or,

⇒ $\frac{F_2}{F_1} =\frac{A_2}{A_1}$

On substituting the value of "A", we get

⇒ $\frac{F_2}{F_1} =\frac{\pi r_2^2}{\pi r_1^2}$

⇒ $\frac{F_2}{F_1} =\frac{r_2^2}{r_1^2}$

On applying cross-multiplication, we get

⇒ $F_2=F_1\times (\frac{r_2}{r_1} )^2$

On substituting the given values, we get

⇒ $=58\times (8.2)^2$

⇒ $=58\times 67.2$

⇒ $=3899.92 \ N$

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3 years ago

The diagram below shows the stars that are nearest to our solar system.

abruzzese [7]

Answer:

no u tried of the same dam

thing

Explanation:

7 0

4 years ago

The crystals that form in slowly cooling magma are generally ____. a. nonexistent c. tiny b. invisible d. large

ki77a [65]

<span>The crystals that form in slowly cooling magma are generally large. </span>

7 0

3 years ago

Read 2 more answers

An aluminium bar 600mm long, with diameter 40mm, has a hole drilled in the center of the bar. The hole is 30mm in diameter and i

ASHA 777 [7]

Answer:

$\delta = 0.385\,m$ (Compression)

Explanation:

The aluminium bar is experimenting a compression due to an axial force, that is, a force exerted on the bar in its axial direction. (See attachment for further details) Under the assumption of small strain, the deformation experimented by the bar is equal to:

$\delta = \frac{P\cdot L}{A \cdot E}$

Where:

$P$ - Load experimented by the bar, measured in newtons.

$L$ - Length of the bar, measured in meters.

$A$ - Cross section area of the bar, measured in square meters.

$E$ - Elasticity module, also known as Young's Module, measured in pascals, that is, newtons per square meter.

The cross section area of the bar is now computed: ( $D_{o} = 0.04\,m$ , $D_{i} = 0.03\,m$ )

$A = \frac{\pi}{4}\cdot (D_{o}^{2}-D_{i}^{2})$

Where:

$D_{o}$ - Outer diameter, measured in meters.

$D_{i}$ - Inner diameter, measured in meters.

$A = \frac{\pi}{4}\cdot [(0.04\,m)^{2}-(0.03\,m)^{2}]$

$A = 5.498 \times 10^{-4}\,m^{2}$

The total contraction of the bar due to compresive load is: ( $P = -180\times 10^{3}\,N$ , $L = 0.1\,m$ , $E = 85\times 10^{9}\,Pa$ , $A = 5.498 \times 10^{-4}\,m^{2}$ ) (Note: The negative sign in the load input means the existence of compressive load)

$\delta = \frac{(-180\times 10^{3}\,N)\cdot (0.1\,m)}{(5.498\times 10^{-4}\,m^{2})\cdot (85\times 10^{9}\,Pa)}$

$\delta = -3.852\times 10^{-4}\,m$

$\delta = -0.385\,mm$

$\delta = 0.385\,m$ (Compression)

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3 years ago