Answer:
The fluid level difference in the manometer arm = 22.56 ft.
Explanation:
Assumption: The fluid in the manometer is incompressible, that is, its density is constant.
The fluid level difference between the two arms of the manometer gives the gage pressure of the air in the tank.
And P(gage) = ρgh
ρ = density of the manometer fluid = 60 lbm/ft³
g = acceleration due to gravity = 32.2 ft/s²
ρg = 60 × 32.2 = 1932 lbm/ft²s²
ρg = 1932 lbm/ft²s² × 1lbf.s²/32.2lbm.ft = 60 lbf/ft³
h = fluid level difference between the two arms of the manometer = ?
P(gage) = 9.4 psig = 9.4 × 144 = 1353.6 lbf/ft²
1353.6 = ρg × h = 60 lbf/ft³ × h
h = 1353.6/60 = 22.56 ft
A diagrammatic representation of this setup is presented in the attached image.
Hope this helps!
Answer: The United States must lead the space race to prevent future wars.
Explanation: Hope this helps
Answer:
275 Kelvin
Explanation:
Coefficient of Performance=11
Answer:
S = 5.7209 M
Explanation:
Given data:
B = 20.1 m
conductivity ( K ) = 14.9 m/day
Storativity ( s ) = 0.0051
1 gpm = 5.451 m^3/day
calculate the Transmissibility ( T ) = K * B
= 14.9 * 20.1 = 299.5 m^2/day
Note :
t = 1
U = ( r^2* S ) / (4*T*<em> t </em>)
= ( 7^2 * 0.0051 ) / ( 4 * 299.5 * 1 ) = 2.0859 * 10^-4
Applying the thesis method
W(u) = -0.5772 - In(U)
= 7.9
next we calculate the pumping rate from well ( Q ) in m^3/day
= 500 * 5.451 m^3 /day
= 2725.5 m^3 /day
Finally calculate the drawdown at a distance of 7.0 m form the well after 1 day of pumping
S = 
where : Q = 2725.5
T = 299.5
W(u) = 7.9
substitute the given values into equation above
S = 5.7209 M
Answer:
1. cout << "Num: " << songNum << endl;
2. cout << songNum << endl;
3. cout << songNum <<" songs" << endl;
Explanation:
//Full Code
#include <iostream>
using namespace std;
int main ()
{
int songNum;
songNum = 5;
cout << "Num: " << songNum << endl;
cout << songNum << endl;
cout << songNum <<" songs" << endl;
return 0;
}
1. The error in the first cout statement is that variable songnum is not declared.
C++ is a case sensitive programme language; it treats upper case and lower case characters differently.
Variable songNum was declared; not songnum.
2. Cout us used to print a Variable that has already been declared.
The error arises in int songNum in the second cout statement.
3. When printing more than one variables or values, they must be separated with <<
