The picture above shows the water cycle. In the water cycle, water travels from the land to the sky and back again. Water leaves the ocean through <u>Evaporation</u><u> </u>and returns to the ocean through <u>Precipitation</u><u> </u><u>and</u><u> </u><u>run-off</u><u>.</u><u> </u>
<u>Thank</u><u> </u><u>You</u><u> </u><u>☺️</u><u> </u><u>☺️</u><u>.</u><u> </u>
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A physical change.
Physical change = can be reverted + doesn't change substance
Chemical = changes substance
Answer:
Compare the solubility of silver iodide in each of the following aqueous solutions:
a. 0.10 M AgCH3COO
b. 0.10 M NaI
c. 0.10 M KCH3COO
d. 0.10 M NH4NO3
1. More soluble than in pure water.
2. Similar solubility as in pure water.
3. Less soluble than in pure water.
Explanation:
This can be explained based on common ion effect.
According to common ion effect the solubility of a sparingly soluble salt decreases further in a solution which has a common ion to it.
The solubility of AgI(s) silver iodide in water is shown below:

a. a. 0.10 M AgCH3COO has a common ion Ag+ with AgI.
So, AgI is less soluble than in pure water in this solution.
b. 0.10 M NaI has a common ion I- with AgI.
So, AgI is less soluble than in pure water in this solution.
c. 0.10 M KCH3COO:
This solution has no common ion with AgI.
So, AgI has similar solubility as in pure water.
d. 0.10 M NH4NO3:
In this solution, AgI can be more soluble than in pure water.
Answer:
The atoms of chlorine are held together by non-polar covalent bonds. Covalent bonds are formed between two or more atoms having zero or very small electronegativity difference. For homonuclear molecules where the two bonding atom are of the same kind, the electronegativity difference is zero.
C. Atoms of chlorine (CI)
(a) 43.6 mg; (b) 520 mg
(a) <em>Mass of phosphoric acid (PA) in a dose
</em>
Mass of PA = 2 tsp × (21.8 mg PA/1 tsp) = 43.6 mg PA
(b) <em>Mass of PA in the bottle
</em>
<em>Step 1</em>. Convert <em>ounces to millilitres
</em>
Volume = 4 oz × (30 mL/1 oz) = 120 mL
<em>Step 2.</em> Calculate the mass of PA
Mass of PA = 120 mL × (21.8 mg PA/5 mL) ≈ 520 mg PA