The C¬C bond in H₃C¬CF₃ (423 kJ/mol) stronger than that in H₃C¬CH₃ (376 kJ/mol) because of the strong negative inductive effect of fluorine atom
<h3>What is Inductive effect?</h3>
When an electron- withdrawing or an electron- releasing species is allow to introduce to a chain of atoms (generally a carbon chain), according to the species corresponding negative or positive charge is start relayed through the carbon chain by the atoms through which it attached. This makes a permanent dipole to arise in the molecule and is referred to as the inductive effect.
<h3>Types of
Inductive effect</h3>
+ inductive effect
- inductive effect
<h3>What is negative inductive effect?</h3>
Whenever an electronegative atom, like halogen, is introduced to a chain of carbon atoms (generally carbon atoms), this results in unequal sharing of electrons which generates a positive charge which is transmitted through the chain.
This make a permanent dipole to arise in the molecule whereas the electronegative atom get a negative charge and the effect is known as the electron-withdrawing inductive effect, or the -I effect.
Thus, we concluded that the C¬C bond in H₃C¬CF₃ (423 kJ/mol) stronger than that in H₃C¬CH₃ (376 kJ/mol) because of the strong negative inductive effect of fluorine atom.
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Answer:
5 L
Explanation:
We'll begin by calculating the molarity of the CaCl₂ solution. This can be obtained as follow:
Mole of CaCl₂ = 0.5 mole
Volume = 2 L
Molarity =?
Molarity = mole /Volume
Molarity = 0.5 / 2
Molarity = 0.25 M
Finally, we shall determine the volume of the diluted solution. This can be obtained as follow:
Molarity of stock solution (M₁) = 0.25 M
Volume of stock solution (V₁) = 2 L
Molarity of diluted solution (M₂) = 0.1 M
Volume of diluted solution (V₂) =?
M₁V₁ = M₂V₂
0.25 × 2 = 0.1 × V₂
0.5 = 0.1 × V₂
Divide both side by 0.1
V₂ = 0.5 / 0.1
V₂ = 5 L
Thus the volume of the diluted solution is 5 L
Answer:
His drives are neither precise not accurate
Explanation:
It is true that his drives are neither precise nor accurate.
Accuracy is the exactness of measurement. It is the closeness of measured values to the true values.
In this problem, the true value is 250 yards, the measured values are 190 yards, 195 yards and 187 yards.
We can conclude that these numbers are very far from the true values. By virtue of that, they are inaccurate.
Precision is the ability to reproduce a set of experimental values. It is the closeness of the measured values to one another.
Jared failed to replicate his measured values over the three trials and so, his readings are not precise.
Therefore, his measurements are both imprecise and inaccurate.
Answer:
Jose is right
Explanation:
As the book is sitting still on the table, it is being acted upon by two forces of equal magnitude and opposite direction. Theses are;
i) The weight of the book
ii) The normal reaction on the book
The weight of the book acts downwards while the normal reaction acts upwards. These two forces exactly counterbalance each other hence the book sits still on the table.
