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3 years ago

Consider the following thermochemical reaction for kerosene:

Chemistry

2 answers:

ch4aika [34]3 years ago

7 0

We have to solve this question using the stoichiometry of the reaction:

The equation of the reaction is;

$2 C12H26(l) + 37 O2(g) -----> 24 CO2(g) + 26 H2O(l) + 15,026 kJ$

According to the question;

Number of moles of CO2 released = 21.3 g/44 g/mol = 0.48 moles

From the stoichiometry of the reaction:

Since;

24 moles of CO2 released 15,026 KJ

0.48 moles of CO2 will release 0.48 * 15,026/24

= 301 KJ of heat.

brainly.com/question/6901180

julsineya [31]3 years ago

3 0

Answer:

2 C12H26(l) + 37 O2(g) ----- > 24 CO2(g) + 26 H2O(l) + 15,026 kJ2C12H26(l)+37O2(g)−−−−−>24CO2(g)+26H2O(l)+15,026kJ

According to the question;

Number of moles of CO2 released = 21.3 g/44 g/mol = 0.48 moles

Since;

24 moles of CO2 released 15,026 KJ

0.48 moles of CO2 will release 0.48 * 15,026/24

= 301 KJ of heat.

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3 years ago

Express the concentration of a 0.0320 M aqueous solution of fluoride, F−, in mass percentage and in parts per million (ppm). Ass

denis23 [38]

Answer:

607 ppm

Explanation:

In this case we can start with the ppm formula:

$ppm=\frac{mg~of~solute}{Litters~of~solution}$

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In other words:

$0.0320~M=\frac{mol}{1~L}$

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$1~L~of~Solution=0.0320~mol~of~solute$

If we use the atomic mass of $F$ (19 g/mol) we can convert from mol to g:

$0.0320~mol~F^-\frac{19~g~F^-}{1~mol~F^-}~=~0.607~g$

Now we can convert from g to mg (1 g= 1000 mg), so:

$0.607~g\frac{1000~mg}{1~g}=607~mg$

Finally we can divide by 1 L to find the ppm:

$ppm=\frac{607~mg}{1~L}=~607~ppm$

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I hope it helps!

4 0

4 years ago

When sulfur burns, it forms sulfur dioxide (SO2). Its chemical reaction is S + O2 → SO2.

Elenna [48]

Answer:

The mass of SO2 will be equal to the sum of the mass of S and O2.

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In this case, the reactants Sulfur (S) and Oxygen (O2) must equal the mass of the product Sulfur Dioxide (SO2). Therefore, the statement "The mass of SO2 will be equal to the sum of the mass of S and O2" is correct.

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3 years ago