A football field is rectangle so each matching side has the same length. Perimeter = adding all sides
keeping in mind that radius is half the diameter, we know this cone has a diameter of 2 inches, so it has a radius of 1 inch, kinda small really for ice-cream, but anyhow.
![\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=1\\ h=6 \end{cases}\implies V=\cfrac{\pi (1)^26}{3}\implies V=2\pi \implies \underset{\textit{rounded up}}{V\approx 6}](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D1%5C%5C%20h%3D6%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20%281%29%5E26%7D%7B3%7D%5Cimplies%20V%3D2%5Cpi%20%5Cimplies%20%5Cunderset%7B%5Ctextit%7Brounded%20up%7D%7D%7BV%5Capprox%206%7D)
Answer:

Step-by-step explanation:
we know that
The length of segment B''C'' is equal to the length of segment BC multiplied by the scale factor
step 1
Find the length of segment BC
the formula to calculate the distance between two points is equal to

we have the points
B(1,-3),C(-3,-3)
substitute the values



The segment B''C'' is equal to the segment BC multiplied by the scale factor
The scale factor is 3
so


substitute

Answer: The new cottage will be 2,560 square feet larger than the small cottage.
Step-by-step explanation:
12x + 5 - 4x + 2x² =
= 2x² + 12x - 4x + 5 = <u>2x²</u><u> </u><u>+</u><u> </u><u>8x</u><u> </u><u>+</u><u> </u><u>5</u>