Answer:
Partial pressure of CO₂ is 406.9 mmHg
Explanation:
To solve the question we should apply the concept of the mole fraction.
Mole fraction = Moles of gas / Total moles
We have the total moles of the mixture, if we have the moles for each gas inside. (3.63 moles of O₂, 1.49 moles of N₂ and 4.49 moles of CO₂)
Total moles = 3.63 mol O₂ + 1.49 mol N₂ + 4.49 mol CO₂ = 9.61 moles
To determiine the partial pressure of CO₂ we apply
Mole fraction of CO₂ → mol of CO₂ / Total moles = P. pressure CO₂ / Total P
Partial pressure of CO₂ = (mol of CO₂ / Total moles) . Total pressure
We replace values: (4.49 moles / 9.61 moles) . 871 mmHg = 406.9 mmHg
Answer:because it isnt flammable
Explanation:water can not be burned
Using the law of <span>dilution:
</span>initial Molarity = 3.5x10⁻⁶ M
<span>Initial volume = 4.00 mL
</span>
final Molarity = ??
final volume = 1.00 mL
Therefore:
Mi x Vi = Mf x Vf
(3.5x10⁻⁶) x 4.00 = Mf x 1.00
1.4x10⁻⁵ = Mf x 1.00
Mf = 1.4x10⁻⁵ / 1.00 =
1.4x10⁻⁵ M
