Answer:
change in internal energy 3.62*10^5 J kg^{-1}
change in enthalapy 5.07*10^5 J kg^{-1}
change in entropy 382.79 J kg^{-1} K^{-1}
Explanation:
adiabatic constant 
specific heat is given as 
gas constant =287 J⋅kg−1⋅K−1

specific heat at constant volume

change in internal energy 

change in enthalapy 

change in entropy



Alpacas were used for their meat, fibers for clothing, and art, and their images in the form of conopas.
Answer:
1. Just because it is small doesn't mean it needs to be excluded. If that were the case I would've been out of my friend group a while ago
2. Look at it it's fricking beautiful (see attachment)
3. It is just a great planet I don't think there needs to be any reason given I meannn you agree?
4. There's no other reason needed it's fricking gorgeous and amazing it needs no other reason. It needs a freaking
opening announcement to announce the arrival of the gorgeouness.
Answer:

Explanation:
= Strain = 0.49
= 3.1 MPa
At t = Time = 32 s
= 0.41 MPa
= Time-independent constant
Stress relation with time

at t = 32 s

The time independent constant is 16.0787 s

At t = 6

From the first equation



Answer:
The work done to get you safely away from the test is 2.47 X 10⁴ J.
Explanation:
Given;
length of the rope, L = 70 ft
mass per unit length of the rope, μ = 2 lb/ft
your mass, W = 120 lbs
mass of the 70 ft rope = 2 lb/ft x 70 ft
= 140 lbs.
Total mass to be pulled to the helicopter, M = 120 lbs + 140 lbs
= 260 lbs
The work done is calculated from work-energy theorem as follows;
W = Mgh
where;
g is acceleration due gravity = 32.17 ft/s²
h is height the total mass is raised = length of the rope = 70 ft
W = 260 Lb x 32.17 ft/s² x 70 ft
W = 585494 lb.ft²/s²
1 lb.ft²/s² = 0.0421 J
W = 585494 lb.ft²/s² = 2.47 X 10⁴ J.
Therefore, the work done to get you safely away from the test is 2.47 X 10⁴ J.