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Grace [21]
3 years ago
8

If each of you pulls with equal force, the rope will not move (the two forces are equal in strength, but opposite in direction).

The forces are ____________. *
Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
8 0

Answer:

i dont know

Explanation:

boooooooooooooooy

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Is this a answer multiple choice or u just answer it
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Bio-chemisty of protain​
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Answer:

Protein biochemistry is the study of proteins. Protein biochemistry is a scientific field dedicated to the study of proteins, complex chains of amino acids which make up the building blocks of all living organisms.

Explanation:

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7 0
3 years ago
8. If a sample of chloroform is initially at 25°C, what is its final temperature if 150.0 g of chloroform
sashaice [31]

Answer:

The final temperature is 31.95° C.

Explanation:

Given that,

Initial temperature of a sample of chloroform, T_i=25^{\circ} C

Mass of chloroform, m = 150 g

It absorbs 1 kJ of heat, Q = 10³ J

The specific heat of chloroform, c = 00.96 J/gºC

We need to find the final temperature. The heat absorbed by an object in terms of specific heat is given by :

Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\\dfrac{Q}{mc}+T_i=T_f\\\\T_f=\dfrac{10^3}{150\times 0.96}+25\\\\=31.95^{\circ} C

So, the final temperature is 31.95° C.

5 0
3 years ago
A stable atom that has a large nucleus most likely contains
Gre4nikov [31]
Most atoms have more neutrons than protons which accounts for basically half of the nucleuses mass.
7 0
4 years ago
Read 2 more answers
A sample of nitrogen is initially at a pressure of 1.7 kPa, a temperature of -10 C and a volume of 7.5 m3. Then the volume is de
zhannawk [14.2K]

Answer:

\boxed{\text{2.6 kPa}}

Explanation:

To solve this problem, we can use the Combined Gas Laws:

\dfrac{p_{1}V_{1} }{T_{1}} = \dfrac{p_{2}V_{2} }{T_{2}}

Data:

p₁ = 1.7 kPa; V₁ = 7.5 m³;  T₁ =   -10 °C

p₂ = ?;          V₂ = 3.8 m³; T₂ = 200  K

Calculations:

(a) Convert temperature to kelvins

T₁ = (-10   + 273.15) K = 263.15 K

(b) Calculate the pressure

\begin{array}{rcl}\dfrac{1.7 \times 7.5 }{263.15} & = & \dfrac{p_{2} \times 3.8}{200}\\\\0.0485 & = & 0.0190p_{2}\\p_{2} & = & \textbf{2.6 kPa}\\\end{array}\\\text{The new pressure of the gas is \boxed{\textbf{2.6 kPa}}}

7 0
3 years ago
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