The correct name of the hydrate iron (ii) sulfite is iron(ii)sulfite heptahydrate
it is gotten as below
find the % composition of FeSO4 = 100-44.26 =55.74 %
find the mole of FeSO4 and H20
= % composition/molar mass
FeSo4 =55.74/151.9 = 0.367 moles
H2O = 44.26/18 =2.459 moles
find the mole ratio by diving each mole with smallest mole
FeSO4 = 0.367/0.367 = 1
H2O = 2.459/0.367 = 7
therefore the name is iron (ii) sulfite heptahydrate is it has seven water molecules
Answer:Volume occupied by the gas at standard pressure is 162.5 L.
Explanation:
Pressure of the gas when it occupies volume of 190 L = 650 mmHg
Volume occupied by the gas when the gas is at standard pressure.
The value of standard pressure = 1 atm = 760 mmHg
According to Boyle's Law: 
(at constant temperature)
Volume occupied by the gas at standard pressure is 162.5 L.
Answer:
they will die because they need to be in salt water
Answer:
2-
Explanation:
For an element to be stable, it must follow the octet rule: an atom will gain, lose or share electrons until its valence shell is complete with 8 electrons.
An element with the valence electron configuration ns²np⁴ has 6 (2+4) electrons in its valence shell. Thus, in order to fulfill the octet, it will gain 2 electrons. As a consequence, it will form an anion with charge 2-.
For Ar :
1 mol ------------ 22.4 L ( at STP )
7.6 mol ---------- x L
x = 7.6 * 22.4
x = 170.24 L
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For C2H3:
1 mol ------------ 22.4 ( at STP)
0.44 mol --------- y L
y = 0.44 * 22.4
y = 9.856 L
hope this helps !.
