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Grace [21]
2 years ago
11

7) A ball is thrown upward at an initial velocity of 8.2 m/s, from a height of 1.8 meters above the ground. The height of the ba

ll h, in metres can be represented, after t seconds, is modelled by the equation h = –4.8t² + 8.2t + 1.8. (a) Determine the height of the ball after 1.7 seconds.

Physics
1 answer:
Dima020 [189]2 years ago
6 0

\\  \tt \longmapsto \: h =  - 4.8 {t}^{2}  + 8.2t + 1.8 \\ \\  \tt \longmapsto \: h =  - 4.8(1.7) {}^{2}  + 8.2 \times 1.7 + 1.8 \\ \\  \tt \longmapsto \:  - 4.8 \times 2.89 + 1.39 + 1.8 \\ \\  \tt \longmapsto \: 13.8 + 1.39 + 1.8 \\ \\  \tt \longmapsto \: 17.06

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