Answer:
Do not see a picture or graph but suspect it would show the golf ball falling faster and striking the ground slightly before the soccer ball.
Probably D: Soccer ball was affected by air resistance more than the golf ball.
Explanation:
Even though heavier, friction loss of the greater surface area soccer ball will counter pull of gravity more than the compact golf ball.
In a vacuum, (no friction) both objects fall at the same rate regardless of mass.
Answer:
0.915 Nm
Explanation:
1 revolution = 2π rad
We can use the following equation of motion to find out the acceleration acting on the disk
where ![\omega v = 2.5 rad/s is the final angular velocity of the disk, [tex]\omega_0](https://tex.z-dn.net/?f=%5Comega%20v%20%3D%202.5%20rad%2Fs%20is%20the%20final%20angular%20velocity%20of%20the%20disk%2C%20%5Btex%5D%5Comega_0)
= 0 rad/s is the initial velocity of the can when it starts from rest, 
is the angular distance traveled, 
is the angular acceleration of the disk, which we care looking for:
The moment of inertia of the solid disk is:
where m is the mass and R is the radius of the disk
The net torque applied is
Answer:
PE = 3.92x10^16J
potential energy
Explanation:
PE = m*g*h
mass of water = 1000kg/m³
(4*10^10m³)*1000kg = 4*10^13kg
PE = (4*10^13kg)*(9.81m/s²)*(100m)
PE = 3.92x10^16J
Answer:
175s
Explanation:
time it takes sunlight to reach the earth in vacuum
C=light speed=299792458m/s
X=1.5x10^8km=1.5x10^11m
c=X/t
T1=X/c
T1=1.5X10^11/299792458=500.34s
time it takes sunlight to reach the earth in water:
First we calculate the speed of light in water taking into account the refractive index
Cw=299792458m/s/1.349=222233104.5m/s
T2=1.5x10^11/222233104.5m/s=675s
additional time it would take for the light to reach the earth
ΔT=T2-T1=675-500=175s
Answer:
The velocity when the ball hits the ground is obtained using v2. 2 = v1. 2 + 2 g Dy with v1=0 and Dy=h. Thus solving for v2 yields 17.1 m/s v2 = 2 g h =.
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