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Xelga [282]
3 years ago
6

Plz HURRY!!!

Mathematics
2 answers:
svetoff [14.1K]3 years ago
5 0

Answer:

I'm pretty sure it's B

Step-by-step explanation:

ivann1987 [24]3 years ago
3 0

Answer:

3/2 times 4/15

Step-by-step explanation:

In division, the quotient times the divisor equals the dividend. This multiplication can be used to check if the math was correct.

Here's an example:

6 / 3 = 2

6 is the dividend, 3 is the divisor, and 2 is the quotient.

2 times 3 is 6, which proves that the quotient times the divisor is the dividend , and it also means that the quotient was correct.

(This example was used because the numbers are nice and easy, so they are good examples for this kind of thing)

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  (0, 2), (5, 5)

Step-by-step explanation:

The w-intercept is the constant in the equation, so you know immediately that (x, w) = (0, 2) is one point on your graph.

Since the value of x is being multiplied by 3/5, it is convenient to choose an x-value that is a multiple of 5. When x=5, we have ...

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Answer:

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Step-by-step explanation:

<em>The </em><em>equation</em><em> </em><em>of </em><em>line </em><em>is </em><em>given </em><em>by </em>

<em>first </em><em>we </em><em>can </em><em>find </em><em>slope </em><em>(</em><em>m</em><em>) </em>

<em>=</em><em> </em><em>(</em><em>y2 </em><em>-</em><em> </em><em>y</em><em>1</em><em>)</em><em> </em><em>/</em><em> </em><em>(</em><em> </em><em>x2</em><em> </em><em>-</em><em> </em><em>x1</em><em>)</em>

<em>=</em><em> </em><em>3</em><em>4</em><em>-</em><em>1</em><em>0</em><em>/</em><em>1</em><em>0</em><em>+</em><em>1</em>

<em> </em><em>=</em><em>2</em><em>4</em><em>/</em><em>1</em><em>1</em>

<em>Now </em><em>the </em><em>equation </em><em>is</em>

<em>y </em><em>-</em><em> </em><em>y1 </em><em>=</em><em> </em><em>m </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>x1) </em>

<em>y </em><em>-</em><em> </em><em>1</em><em>0</em><em> </em><em>=</em><em> </em><em>2</em><em>4</em><em>/</em><em>1</em><em>1</em><em> </em><em>(</em><em> </em><em>x </em><em>+</em><em>1</em><em>1</em><em>)</em>

<em>11 </em><em>(</em><em> </em><em>y </em><em>-</em><em> </em><em>1</em><em>0</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em>4</em><em> </em><em>(</em><em>x </em><em>+</em><em> </em><em>1</em><em>1</em><em>)</em>

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<em>which </em><em>is </em><em>the </em><em>required </em><em>equation </em>

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