Answer:

Step-by-step explanation:

Adding and Subtracting 1 to the Numerator

Dividing Numerator seperately by 

Here integral of 1 is x +c1 (where c1 is constant of integration
----------------------------------(1)
We apply method of partial fractions to perform the integral
=
------------------------------------------(2)

1 =
-------------------------(3)
Substitute x= 1 , -1 , i in equation (3)
1 = A(1+1)(1+1)
A = 
1 = B(-1-1)(1+1)
B = 
1 = C(i-1)(i+1)
C = 
Substituting A, B, C in equation (2)
= 
On integration
Here 
=
-
-
+ c2---------------------------------------(4)
Substitute equation (4) back in equation (1) we get

Here c1 + c2 can be added to another and written as c
Therefore,

In math the fraction 5/6 means 5 and 6 tenths.
Answer:
All Real Numbers
Step-by-step explanation:
Step 1:
3x - 9 = 3 ( x - 3 ) Equation
Step 2:
3x - 9 = 3x - 9 Multiply
Step 3:
- 9 = - 9 Subtract 3x on both sides
Answer:
All Real Numbers
Hope This Helps :)
The answer the 3,
First you have to apply the exponent rule which is 1 - 3• 1/g
Then you multiply the fractions - 1•3/g
Then multiply the numbers 1 and 3, which is 3, so there you have it 3/g, or 3, they’re the same thing.