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NISA [10]
3 years ago
7

A 30-g car rolls from a hill 12 cm high and is traveling at 154 cm/s as it travels along a 275 cm horizontal track. What is the

momentum of the car?
Physics
1 answer:
Bond [772]3 years ago
8 0
Momentum of the car is 46.2 kgm/s
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If the kinetic and potential energy in a system are equal, then the potential energy increases. What happens as a resul
Kobotan [32]

-- If the system is 'closed', then nothing ... including energy ... can get in or out, and the total energy inside has to be constant.

If half of the energy in the system starts out as potential energy and the rest starts out as kinetic, and then the potential energy increases, there's only one place the increase could have come from ... it could only have been converted from kinetic energy.  So the <em>kinetic energy</em> in the system <em>must</em> <em>decrease</em>.

In fact, this isn't even a "result".  The kinetic energy has to decrease <em><u>before</u></em> the potential energy can increase, because that's where the increase has to come from.

If the system is 'open', then energy can come in and go out.  If the potential energy inside suddenly increases, we don't know where it came from, so we can't say anything about what happens to the system.

7 0
3 years ago
Which statement accurately describes the chemical symbol of an element?
Mekhanik [1.2K]

The chemical symbol always begins with a capital letter.

.


8 0
3 years ago
Read 2 more answers
Key difference of the celsius scale and kevin scale
mixer [17]

Their 'degrees' are the same size.  The difference between the Celsius
and Kelvin scales is their zero-point.  Zero Kelvin is the absolute zero of
nature and Physics.  Zero Celsius is the melting/freezing point of water,
273.15 higher than absolute zero.

6 0
3 years ago
Calculate the change in length of concrete sidewalk (coefficient of linear expansion for concrete is 12*10^-6/celcius) that is 1
anyanavicka [17]

Answer:

The answer to your question is 5.4 cm

Explanation:

This problem refers to calculate the change in length in one dimension due to a change in temperature.

Data

α = 12 x 10⁻⁶

Lo = 150 meters

ΔT = 30 °C

Formula

                    ΔL/Lo = αΔT

solve for ΔL

                    ΔL = αLoΔT

Substitution

                    ΔL = (12 x 10⁻⁶)(150)(30)

Simplification

                    ΔL = 0054 m = 5.4 cm

7 0
3 years ago
What is the amount of work done when a force of 10N moves a 20kg mass of 8 meters?
Nataly_w [17]

Yo sup??

we should know that

work done=force*displacement

W=F.s

F=10 N

s=8 m

therefore

W=10*8

=80 N

Hope this helps.

3 0
2 years ago
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