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3 years ago

7

A 30-g car rolls from a hill 12 cm high and is traveling at 154 cm/s as it travels along a 275 cm horizontal track. What is the

momentum of the car?

1 answer:

Bond [772]3 years ago

8 0

Momentum of the car is 46.2 kgm/s

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A total resistance of 3.03 Ω is to be produced by connecting an unknown resistance to a 12.18 Ω resistance. (a) What must be the

insens350 [35]

Answer:

(a) 4.0334Ω

(b)parallel

Explanation:

for resistors connected in parallel;

$\frac{1}{R_{eq} } =\frac{1}{R1}+\frac{1}{R2}$

Req =3.03Ω , R1 =12.18Ω

$\frac{1}{3.03 } =\frac{1}{12.18}+\frac{1}{R2}$

$\frac{1}{R2}=\frac{1}{3.03 }-\frac{1}{12.18}$

$\frac{1}{R2}=0.2479$

R2=1/0.2479

R2=4.0334Ω

(b)parallel connection is suitable for the desired total resistance. series connection can not be used to achieve a lower resistance as the equation for series connection is.

Req = R1+R2

3 0

3 years ago

Two identical bodies are sliding toward each other on a frictionless surface. One moves at 1 m/s and the other at 2 m/s. They co

mario62 [17]

Answer:

$V=\dfrac{3}{2}\ m/s$

Explanation:

Two identical bodies are sliding toward each other on a frictionless surface.

Initial speed of body 1, m₁ = 1 m/s

Initial speed of body 2, m₂ = 2 m/s

They collide and stick.

We need to find the speed of the combined mass. Let V is the speed of the combined mass.

Using the conservation of momentum.

$m_1u_1+m_2u_2=V(m_1+m_2)$

We have, m₁ = m₂ = m

$m\times 1+m\times 2=(m+m)V\\\\m+2m=2m\times V\\\\3m=2mV\\\\V=\dfrac{3}{2}\ m/s$

So, the speed of the combined mass is $\dfrac{3}{2}\ m/s$ .

6 0

3 years ago

A coil of wire is comprised of 5 turns, has a current of 2 mA running through it, and a net magnetic field at its center of B is

VARVARA [1.3K]

Answer:

<em>20cm</em>

Explanation:

<em>A coil wire comprises of 5 turns, it has a current of 2mA </em>

<em>A net magnetic field at the center of B is equal to Mu over 40 end fractions times T</em>

<em>The radius of a coil of wire with N turns is r = 0.28 m. A clockwise current of Icoil = 1.0 A flows in the coil,</em>

<em>Therefore 40/2mA = 20</em>

6 0

3 years ago

I WILL MARK YOU THE BRAINLIEST NO LINKS

gladu [14]

Answer:

buoyant force

Explanation:

just trust meeee

4 0

3 years ago

Read 2 more answers

If you drop a ball off a cliff, it starts out at 0 m/s. after 1 s, it will be traveling at about 10 m/s. if air resistance is re

anastassius [24]

The ball dropped of a cliff will have a final velocity of 19.6 m/s at 2s

The free fall formula and the procedure we will use is:

fv = g* t

Where:

fv = final velocity
g = acceleration due to gravity
t = time taken
h = height traveled

Information of the problem:

g = 9.8 m/s².
t = 2 s
vf = ?

Applying final velocity formula we get:

fv = g* t

fv = 9.8 m/s² * 2 s

fv = 19.6 m/s

<h3>What is free fall?</h3>

It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.

Learn more about free fall at brainly.com/question/11257529

#SPJ4

5 0

2 years ago