Answer:
THE MOLARITY OF THE ACID IS 0.232M
Explanation:
Molarity is the number of moles of solute per liter of a solution.
In titration, the molarity of the acid and the molarity of the base are related by this equation:
Ca VA / CbVb = na / nb
Ca = concentration of the acid = ?
Va = volume of the acid = 49 mL
Cb = concentration of the base = 0.333M
Vb = volume of the base = 68.4mL
Na = number of mole of acid = 1
Nb = number of mole of base = 2
Equation for the reaction:
H2SO4 + 2NaOH --------> Na2SO4 + 2H2O
Solving for the molarity of the acid, we have :
Ca = CbVbNa / VaNb
Ca = 0.333M * 68.4mL * 1 / 49mL *2
Ca = 22.7772 * 10^-3 / 98 *10^-3
Ca = 0.232M
The molarity of the acid is therefore 0.232M.
