Wave speed = (frequency) x (wavelength)
= (266 /sec) x (1.3 meters)
= 345.8 meters/sec
The displacement of the train after 2.23 seconds is 25.4 m.
<h3>Resultant velocity of the train</h3>
The resultant velocity of the train is calculated as follows;
R² = vi² + vf² - 2vivf cos(θ)
where;
- θ is the angle between the velocity = (90 - 51) + 37 = 76⁰
R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)
R² = 129.75
R = √129.75
R = 11.39 m/s
<h3>Displacement of the train</h3>
The displacement of the train is the change in position of the train after a given period of time.
The displacement is calculated as follows;
Δx = vt
Δx = 11.39 m/s x 2.23 s
Δx = 25.4 m
Thus, the displacement of the train after 2.23 seconds is 25.4 m.
Learn more about displacement here: brainly.com/question/2109763
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Answer:
Explanation:
The difference in time will be due to travel through atmosphere where speed of light slows down. If t be the thickness of atmosphere and c be the speed of light in space and μ be the refractive index of atmosphere difference in travel time will be as follows .
difference = \frac{2t\mu }{c}-\frac{2t }{c}
=\frac{2t}{c }\left ( 1-\mu \right )
Now t = 40 x 10³m ,μ = 1.000293 , c = 3 x 10⁸.
difference =\frac{2t\mu }{c}-\frac{2t }{c}
=\frac{2t}{c }\left ( \mu -1 \right )\\
=\frac{ 2\times 40\times 10^3}{3\times10^3 }\left ( 1.000293-1 \right )\\
=7.81\times 10^{-3}
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