
<em>Hope it helps and is useful :)</em>
The answer would be 56.10
Let a and b represent the heights of the corresponding buildings (in meters).
... a = b +271 . . . . . . . a is 271 meters taller than b
... 2b -a = 211 . . . . . . if a is subtracted from twice b, the result is 211
Use the expression for a in the first equation to substitute for a in the second.
... 2b - (b+271) = 211
... b = 482 . . . . . . . . . . . simplify and add 271
... a = b +271 = 753
Building a is 753 meters tall; building b is 482 meters tall.
Each student would get 1.6 brownies
Step 1: Subtract -2 from both sides.<span><span><span><span>
m2</span>+<span>4m</span></span>−<span>(<span>−2</span>)</span></span>=<span><span>−2</span>−<span>(<span>−2</span>)</span></span></span><span><span><span><span>
m2</span>+<span>4m</span></span>+2</span>=0</span>
Step 2: Use quadratic formula with a=1, b=4, c=2.<span>
m=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>
m=<span><span><span>−<span>(4)</span></span>±<span>√<span><span><span>(4)</span>2</span>−<span><span>4<span>(1)</span></span><span>(2)</span></span></span></span></span><span>2<span>(1)</span></span></span></span><span>
m=<span><span><span>−4</span>±<span>√8</span></span>2</span></span><span><span>
m=<span><span>−2</span>+<span><span><span>√2</span><span> or </span></span>m</span></span></span>=<span><span>−2</span>−<span>√2</span></span></span><span>
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