Lighting a match
hope the answer helped!
Answer:
height is 69.68 m
Explanation:
given data
before it hits the ground = 46 % of entire distance
to find out
the height
solution
we know here acceleration and displacement that is
d = (0.5)gt² ..............1
here d is distance and g is acceleration and t is time
so when object falling it will be
h = 4.9 t² ....................2
and in 1st part of question
we have (100% - 46% ) = 54 %
so falling objects will be there
0.54 h = 4.9 (t-1)² ...................3
so
now we have 2 equation with unknown
we equate both equation
1st equation already solve for h
substitute h in the second equation and find t
0.54 × 4.9 t² = 4.9 (t-1)²
t = 0.576 s and 3.771 s
we use here 3.771 s because 0.576 s is useless displacement in the last second before it hits the ground is 46 % of the entire distance it falls
so take t = 3.771 s
then h from equation 2
h = 4.9 t²
h = 4.9 (3.771)²
h = 69.68 m
so height is 69.68 m
Answer:
0.064 m
Explanation:
When a spring is stretched/compressed, the force exerted in the spring is related to the elongation of the spring by the equation:
where:
F is the force applied
k is the spring constant
x is the stretching/compression of the spring
In this problem, we have:
is the force applied by the kid on the spring
k = 128 N/m is the spring constant
Solving for x, we find how far the spring stretches:
Answer:
velocity (v) =distance(s) ÷ time (t)
Explanation:
v=s÷t
s=v×t
s=3×3.4
s= 10.2m
