Move the objects faster to get more friction.
Answer:
Between 2.0 s and 4.0 s (B and C)
Between 5.0 s and 8.0 s (D and E)
Between 10.0 s and 11.0 s (F and G)
Explanation:
The graph shown in the figure is a velocity-time graph, which means that:
- On the x-axis, the time is plotted
- On the y-axis, the velocity is plotted
Therefore, this means that the object is not moving when the line is horizontal (because at that moment, the velocity is constant, so the object is not moving). This occurs in the following intervals:
Between 2.0 s and 4.0 s (B and C)
Between 5.0 s and 8.0 s (D and E)
Between 10.0 s and 11.0 s (F and G)
From the graph, it would be possible to infer additional information. In particular:
- The area under the graph represents the total distance covered by the object
- The slope of the graph represents the acceleration of the object
Answer:
H(max) = (v²/2g)
Explanation:
The maximum height the ball will climb will be when there is no friction at all on the surface of the hill.
Normally, the conservation of kinetic energy (specifically, the work-energy theorem) states that, the change in kinetic energy of a body between two points is equal to the work done in moving the body between the two points.
With no frictional force to do work, all of the initial kinetic emergy is used to climb to the maximum height.
ΔK.E = W
ΔK.E = (final kinetic energy) - (initial kinetic energy)
Final kinetic energy = 0 J, (since the body comes to rest at the height reached)
Initial kinetic energy = (1/2)(m)(v²)
Workdone in moving the body up to the height is done by gravity
W = - mgH
ΔK.E = W
0 - (1/2)(m)(v²) = - mgH
mgH = mv²/2
gH = v²/2
H = v²/2g.
Answer:
Campfires top the list of ways that humans start wildfires, the U.S. Forest Service said. Typically, campfires either grow out of control and the people who built the fire do not have a way to stop it, or they fail to extinguish the fire properly, allowing the fire to re-ignite after they leave.
Explanation:
Answer:
Total mechanical energy is the sum of potential energy plus kinetic energy. The kinetic energy will be 250 [J] and the potential energy is zero, therefore Total mechanical energy will be 250 + 0 =250[J]
Explanation:
This is a problem that applies the principle of energy conservation, i.e. mechanical energy that will be transformed into kinetic energy. We need to identify what kind of energy we have depending on the position of the ball with respect to the reference axis we take.
The reference axis or reference point is the point at which the potential energy is equal to zero, for this case we will take the ground as our reference point.
We know that the potential energy is defined by:
![E_{p}=m*g*h\\ where:\\m=mass[kg]\\g=gravity[m/s^2]\\h=elevation[m]](https://tex.z-dn.net/?f=E_%7Bp%7D%3Dm%2Ag%2Ah%5C%5C%20where%3A%5C%5Cm%3Dmass%5Bkg%5D%5C%5Cg%3Dgravity%5Bm%2Fs%5E2%5D%5C%5Ch%3Delevation%5Bm%5D)
We can clear the mass from this equation:
![m=\frac{E_{p} }{(g*h)} \\m=\frac{250 }{(9.81*5)} \\\\m=5.09[kg]](https://tex.z-dn.net/?f=m%3D%5Cfrac%7BE_%7Bp%7D%20%7D%7B%28g%2Ah%29%7D%20%5C%5Cm%3D%5Cfrac%7B250%20%7D%7B%289.81%2A5%29%7D%20%5C%5C%5C%5Cm%3D5.09%5Bkg%5D)
When this body falls its potential energy will decrease but its kinetic energy will increase and reach its maximum value when the ball reaches the ground.
In such a way that its potential energy would be transformed into kinetic energy.
![E_{k} = E_{p} \\E_{k} =kinetic energy [J]](https://tex.z-dn.net/?f=E_%7Bk%7D%20%3D%20E_%7Bp%7D%20%5C%5CE_%7Bk%7D%20%3Dkinetic%20energy%20%5BJ%5D)
Since the potential energy has been transformed all into kinetic energy the amount of energy is conserved, therefore the total mechanical energy will remain the same.
