All categories

2 years ago

A solid is formed when two liquids are combined because...

Chemistry

2 answers:

satela [25.4K]2 years ago

5 0

Answer:

yes sir

Explanation:

Slav-nsk [51]2 years ago

3 0

Answer:

of chemical reactions

Explanation:

sorry if that’s wrong not understanding the question

You might be interested in

How many mg of metallic ions are in 1.0 mL of 0.10 M LINO3

Anton [14]

Answer:

0.6941 mg

Explanation:

First we calculate how many LiNO₃ moles there are, using the given concentration and volume:

1.0 mL * 0.10 M = 0.10 mmol LiNO₃

As 1 mol of LiNO₃ contains 1 mol of Li, in the problem solution there are 0.10 mmol of Li (the only metallic ion present).

Now we convert Li milimoles into miligrams, using its atomic mass:

0.10 mmol Li * 6.941 mg/mmol = 0.6941 mg

8 0

2 years ago

When body temperature rises during physical activity, which thermoregulatory response is stimulated?

navik [9.2K]

Answer: Heat dissipation mechanism

Explanation: Heat dissipation mechanism is a thermoregulatory response in humans whereby the hypothalamus of the brain initiates certain processes to reduce the high body temperature. Eg, sweating is initiated which helps cool down the body temperature, also superficial arteries are dilated, thereby leading to flushing and decreasing heatloss into the air. And metabolic heat production is also reduced.

8 0

3 years ago

Please help me with this basic organic conversion. use the shortest way to do it

jonny [76]

Answer:

See explanation

Explanation:

This conversion must go through a sequence of steps as i have shown in the image attached to this answer.

The acetone is converted to propan-2-ol using LiAlH4, THF and acid. The propan-2-ol may be converted to propene by E2 elimination. Addition of HBr yields 2-bromo propane.

The Wurtz reaction converts 2-bromo propane to 2,3- dimethyl butane. This can be brominated in the presence of light to yield 3-bromo-2,3-dimethyl butane. Elimination of HBr using a base leads to the formation of the required product as shown.

7 0

2 years ago

PLEASE HELP!!!!!!!!! 12 POINTS!!!!!!!

Nimfa-mama [501]

Ocean-dwelling I would say.

4 0

3 years ago

Read 2 more answers

For the Zn - Cu^2+ voltaic cell Zn(s) + Cu^2+(aq, 1M) + Cu(s) E degree _cell = 1.10 V Given that the standard reduction potentia

Fittoniya [83]

Answer : The value of $E^o_{(Cu^{2+}/Cu)}$ is, 0.34 V

Explanation :

Here, copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction: $Cu^{2+}+2e^-\rightarrow Cu$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

$Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$