All categories

2 years ago

A solid is formed when two liquids are combined because...

Chemistry

2 answers:

satela [25.4K]2 years ago

5 0

Answer:

yes sir

Explanation:

Slav-nsk [51]2 years ago

3 0

Answer:

of chemical reactions

Explanation:

sorry if that’s wrong not understanding the question

You might be interested in

Are pterosaurs more closely related to turtles or to crocodilians? Explain your answer.

Reptile [31]

Answer:

Pterosaurs are more closely related to crocodilians. They share a more recent common ancestor than do pterosaurs and turtles.

Explanation:

Hope this Helps! :)

8 0

2 years ago

Why would fluorine, chlorine, and bromine be placed in the same group (the halogens) in the periodic table of elements? (1 point

inna [77]

D. They share chemical properties.

7 0

2 years ago

What has the same number of valence electrons in the outermost shell?

algol [13]

Answer:

Groups

Explanation:

Elements with the same number of valence electrons are found in the same column(group) of the Periodic Table.

4 0

2 years ago

A 237g sample of molybdnum metal is heated to 100.1 0C and then dropped into an insulated cup containing 244 g of water at 10.0

miv72 [106K]

Answer:

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

Explanation:

We consider the system formed by the molybdenum metal and water as our system, a control mass inside an insulated cup, that is, a container that avoids any energy and mass interactions between system and surroundings.

From statement we notice that metal is cooled down whereas water is heated. According to the First Law of Thermodynamics, we know that:

$Q_{metal} - Q_{water} = 0$

$Q_{metal} = Q_{water}$

Where:

$Q_{water}$ - Heat received by water, measured in joules.

$Q_{metal}$ - Heat released by metal, measured in joules.

Now we expand this identity by definition of sensible heat:

$m_{metal}\cdot c_{metal}\cdot (T_{m,o}-T) = m_{water}\cdot c_{water}\cdot (T-T_{w,o})$

The specific heat of the metal is cleared within equation above:

$c_{metal} = \frac{m_{water}\cdot c_{water}\cdot (T-T_{w,o})}{m_{metal}\cdot (T_{m,o}-T)}$

If we know that $m_{water} = 0.237\,kg$ , $m_{metal} = 0.244\,kg$ , $c_{water} = 4186\,\frac{J}{kg\cdot ^{\circ}C}$ , $T_{w,o} = 10\,^{\circ}C$ , $T_{m,o} = 100.10\,^{\circ}C$ and $T = 15.30\,^{\circ}C$ , the specific heat of molybdenum is:

$c_{metal} = \frac{(0.237\,kg)\cdot \left(4186\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (15.30\,^{\circ}C-10\,^{\circ}C)}{(0.244\,kg)\cdot (100.10\,^{\circ}C-15.30\,^{\circ}C)}$

$c_{metal} = 254.119\,\frac{J}{kg\cdot ^{\circ}C}$

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

5 0

2 years ago

LINKS WILL BE REPORTED PLEASE HELP

erastovalidia [21]

C. the denser the plants the better.

Answer:

7 0

2 years ago

Read 2 more answers