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What kind of cord is this no links please

Ne4ueva [31]

Answer:

if i'm not mistaken that's either a plug in cord for a certain device, or what i am assuming to be a usb software cord.

Explanation:

8 0

2 years ago

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If a microwave oven produces electromagnetic waves with a frequency of 2.30 ghz, what is their wavelength?

vovikov84 [41]

Answer: wavelength is $1.30 \times 10^8 nm.$

The frequency of the microwave is, f = 2.30 GHz.

To Find frequency use the formula:

$c=f$ λ

Where, c is the speed of electromagnetic wave or light. f is the frequency, and λ is the wavelength of light.

Rearranging, $\lambda = \frac{c}{f}$

Plug in the values,

$\lambdam = \frac{3 \times 10^8 m/s}{2.30 GHz\frac{10^9 Hz}{1 GHz}}=0.130 m\frac{10^9 nm}{1 m} = 1.30 \times 10^8 nm.$

5 0

3 years ago

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A piece of wood and a piece of steel are at the same temperature; however, the steel feels hotter. This is because the steel has

Vikentia [17]

The steel traps the heat more making it hotter,you put this twice by the way.

3 0

3 years ago

A person is standing on and facing the front of a stationary skateboard while holding a construction brick. The mass of the pers

Inessa [10]

Answer:

v₁ = -0.8087 m / s

Explanation:

To solve this problem we can use the conservation of momentum, for this we define a system formed by the man, the skateboard and the brick, therefore the force during the separation is internal and the momentum is conserved

Initial instant. When they are united

p₀ = 0

Final moment. After throwing the brick

$p_{f}$ = (m_man + m_skate) v1 + m_brick v2

the moment is preserved

p₀ = p_{f}

0 = (m_man + m_skate) v₁ + m_brick v₂

v₁ = - $\frac{ m_{brick} }{m_{man} + m_{skate} } v_{2}$

the negative sign indicates that the two speeds are in the opposite direction

let's calculate

v₁ = - $\frac{2.5}{67 + 4.10} 23.0$

v₁ = -0.8087 m / s

6 0

3 years ago

In a science museum, a 110 kg brass pendulum bob swings at the end of a 13.9 m -long wire. the pendulum is started at exactly 8:

saw5 [17]

The number of oscillations completed by the pendulum is 2736.

The amplitude of the pendulum is 3.47 m.

The given motion is an underdamped motion. So its frequency will be similar to that of a simple harmonic motion.

The frequency of oscillation is defined as the number of oscillations completed in unit time. It is calculated using the formula.

f=(1/2π)*√(l/g)

where f is the frequency, l is the length of the pendulum, and g is the acceleration due to gravity.

Given the length of the wire l=13.9 m and acceleration due to gravity g=9.8 m/s^2. The frequency of oscillation is:

f=(1/(2*3.14)) * √(13.9/9.8)

f=0.19 Hz (approximately)

Since the pendulum started oscillating at 8:00 am, 4 hours has been passed when it shows 12:00 pm. So time t=4 hours or t=4*3600. Hence t=14400 s. The total number of oscillations is then given by the formula,

n=ft

where n is the number of oscillations.

n=0.19*14400=2736.

In damping motion, the amplitude of the pendulum decreases with time. The amplitude of the pendulum is given by the formula,

A' = A exp (-b*t)

where A' is the amplitude after time t, A is the initial amplitude, b is the damping constant, and t is the time.

Here A=1.2 m, b=0.010 kg/s and t=14400 s.

A' = 1.2 exp (-0.010*14400)

A'=3.47 m (approximately)

Learn more about amplitude.

brainly.com/question/21632362

#SPJ4

5 0

2 years ago