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nalin [4]
3 years ago
8

A 1055-kg van, stopped at a traffic light, is hit directly in the rear by a 660-kg car traveling with a velocity of 2.00 m/s. As

sume that the transmission of the van is in neutral, the brakes are not being applied, and the collision is elastic. What is the final velocity of each vehicle
Physics
1 answer:
frosja888 [35]3 years ago
8 0

Answer:

<h3>0.77m/s</h3>

Explanation:

According to law of conservation of energy

m1u1 + m2 u2 = (m1+m2)v

m1 and m2 are the masses of the bodies

u1 and u2 are the initial velocities

v is the final velocity after collision

Substitute the given values into the formula

1055(0) + 660(2) = (1055+660)v

0+1320 = 1715v

v = 1320/1715

v = 0.77m/s

Hence the final velocity of each vehicle is 0.77m/s

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A spy satellite uses a telescope with a 1.7-m-diameter mirror. It orbits the earth at a height of 180 km.
WINSTONCH [101]

Answer: the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

Explanation:

Given that;

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wavelength λ = 500 nm = 5 × 10⁻⁹ m

Now Angular separation from the peak of the central maximum is expressed as;

sin∅= 1.22 λ / d

sin∅ = (1.22 × 5 × 10⁻⁹) / 1.7

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we know that;

 sin∅  = object separation / distance from telescope

object separation =   sin∅ × distance from telescope

object separation = 3.588 × 10⁻⁷  × 180 × 10³

object separation =6.45 × 10⁻² m

then we convert to centimeter

object separation = 6.45 cm

Therefore the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

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3 years ago
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Explanation:

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Explanation:

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Answer: im just trying to get some points so i can answer my question.

sorry

Explanation:

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