Answer:
Westward
Explanation:
This is in line with the Fleming's left hand rule.
Answer:
<em>The cliff is 5916.75 m far</em>
Explanation:
Echo: This is a sound heard after the reflection of sound wave from a plane surface.
v = 2x/t........................... Equation 1
making x the subject of the equation above,
x = vt/2........................... Equation 2
Where v = speed of sound in air, x = distance of the cliff, t = time to produce an echo
<em>Given: t = 34.50 s,</em>
<em>Constant: v = 343 m/s</em>
<em>Substituting these values into equation 2,</em>
<em>x = 343×34.5/2</em>
<em>x = 5916.75 m.</em>
<em>Thus the cliff is 5916.75 m far</em>
Answer:
E = 1/2 M V^2 + 1/2 I ω^2 = 1/2 M V^2 + 1/2 I V^2 / R^2
E = 1/2 M V^2 (1 + I / (M R^2))
For a cylinder I = M R^2
For a sphere I = 2/3 M R^2
E(cylinder) = 1 + 1 = 2 omitting the 1/2 M V^2
E(sphere) = 1 + 2/3 = 1.67
E(cylinder) / E(sphere) = 2 / 1.67 = 1.2
The cylinder initially has 1.20 the energy of the sphere
The PE attained is proportional to the initial KE
H(sphere) = 2.87 / 1/2 = 2.40 m since it has less initial KE
Height increase h = R*(1 - cosΘ) = 1.2*(1-cos3.5°) = .00224 m.
<span>½Mbl*Vbl² = Mbl*g*h → </span>
<span>Vbl = √(2gh) = .2095 m/s </span>
<span>This is the initial velocity of the block. From momentum considerations, </span>
<span>Mbt*Vbt = Mbl*Vbl → </span>
<span>Vbt = (Mbl/Mbt)*Vbl = (5/.002)*.2095 = 523.8 m/s
this is what i think the answer is im not for sure though... hope it helps...</span>