2C4H10 + 13O2 = 8CO2 + 10H2O
1. (2.06g C4H10)/(58.12 g/mol C4H10) = 0.035mol C4H10
2. (0.035molC4H10)(10 mol H2O/2mol C4H10) = 0.177mol H2O
3. (0.177mol H2O)(18.01g/mol H2O) = 3.19g H2O
Alkali: Group 1(I A). Halogens: group 17 (VII A)
Answer:
3.011 × 10²³ particles
Explanation:
Given data:
Number of moles = 0.5 mol
Number of particles = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
one mole of substance = 6.022 × 10²³ particles
For 0.5 mole of substance:
0.5 mol × 6.022 × 10²³ particles / 1 mol
3.011 × 10²³ particles
The Everglades and the Louisiana wetan are the same
Answer:
B) 244.5
Explanation:
2.62 torr =349.3046 pascals.
349.3046*0.7 sq meter = 244.5 N
