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Ludmilka [50]
4 years ago
7

Leading edge flaps can be used to decrease (or eliminate) the leading edge suction peak at a desired lift coefficient. When airf

oils are designed for cruise performance, however, a better strategy is to design an airfoil that produces the correct lift with no suction peak using a cambered airfoil (i.e. without including leading edge flaps). To see that this is possible, we will consider the NACA 44XX airfoils. Also, p is the location of the maximum camber and is second digit/10. Apply thin airfoil theory to answer the following questions: (a) Determine the angle of zero lift for the 44XX airfoils (b) Determine the angle at which the suction peak is eliminated. We will call this the design angle of attack for the 44XX airfoils (c) What is the design lift coefficient for the 44XX airfoils (i.e. the lift coefficient at the design angle of attack)?
Physics
1 answer:
Alik [6]4 years ago
5 0

Answer:

An investigation is made to determine the performance of simple thin airfoils in the slightly supersonic flow region with the aid of the nonlinear transonic theory first developed by von Kármán[1]. Expressions for the pressure coefficient across an oblique shock and a Prandtl-Meyer expansion are developed in terms of a transonic similarity parameter. Aerodynamic coefficients are calculated in similarity form for the flat plate and asymmetric wedge airfoils, and curves are plotted. Sample curves for a flat plate and a specific asymmetric wedge are plotted on the usual coordinate grid of Cl, Cd,andCmc/4versus angle of attack and Cl versus Mach Number to illustrate the apparent features of nonlinear flow.

Explanation:

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What happens to the forces acting on a falling object at terminal velocity?
xenn [34]

Answer: Objects falling through a fluid eventually reach terminal velocity. At terminal velocity, the object moves at a steady speed in a constant direction because the resultant force acting on it is zero.

8 0
3 years ago
An astronaut shipwrecked on a distant planet with unknown characteristics is on top of a cliff, which she wishes to descend. She
alexandr402 [8]

Answer:

y = 9.64 m

Explanation:

This exercise should be solved using kinematics in one dimension, let's write the equations for the two cases presented

The rock is released

         y = y₀ + V₀₁ t₁ - ½ g t₁²

In this case the speed starts is zero

         y = y₀ - ½ g t₁²

The rock ​​is thrown up

       y = y₀ + v₀² t₂ -½ g t₂²

The height that reaches the floor is zero

       y₀ - ½ g t₁² = y₀ + v₀₂ t₂ - ½ g t₂²

We use the initial velocity with the equation

         v₂² = v₀₂² - 2 g y

At the point of maximum height v₂ = 0

         v₀₂ = √ (2 g y_{max})

        g (-t₁² + t₂²) = 2 √ (2 g y_{max}) t₂²

        g (- 4.15² + 6.30²) = 2 √ (2 2 g) 6.3

        g (22.4675) = 25.2 √ g

        g² = 2²5.2 / 22.4675 g

        g = 1.12 m / s²

Having the value of g we can use any equation to find the height

        y = ½ g t₁²

       y = ½ 1.12 4.15²

        y = 9.64 m

5 0
3 years ago
What type of metal are conducting wires most often made of?<br><br> #16
docker41 [41]

Answer:

here

Explanation:

Copper is commonly used as an effective conductor in household appliances and in electrical equipment in general. Because of its low cost, most wires are copper-plated. You will often find electromagnet cores normally wrapped with copper wire

3 0
2 years ago
In order for water to condense on an object, the temperature of the object must be ______ the dewpoint temperature.
enyata [817]

Answer:

at   ( or below)

Explanation:

at the dewpoint.......water will condense out of the air onto the surface

7 0
2 years ago
If the direction of the position is north and the direction of the velocity is up, then what is the direction of the angular mom
Kay [80]

Answer:

the direction of angular momentum = EAST

Explanation:

given

Direction of position = r = north

Direction of velocity = v = up

angular momentum = L = m(r x v)

where m is the mass, r is the radius, v is the velocity

utilizing the right hand rule, the right finger heading towards the course of position vector and curl them toward direction of velocity, at that point stretch thumb will show the bearing of the angular momentum.

then L = north x up = East

6 0
3 years ago
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