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Ludmilka [50]
3 years ago
7

Leading edge flaps can be used to decrease (or eliminate) the leading edge suction peak at a desired lift coefficient. When airf

oils are designed for cruise performance, however, a better strategy is to design an airfoil that produces the correct lift with no suction peak using a cambered airfoil (i.e. without including leading edge flaps). To see that this is possible, we will consider the NACA 44XX airfoils. Also, p is the location of the maximum camber and is second digit/10. Apply thin airfoil theory to answer the following questions: (a) Determine the angle of zero lift for the 44XX airfoils (b) Determine the angle at which the suction peak is eliminated. We will call this the design angle of attack for the 44XX airfoils (c) What is the design lift coefficient for the 44XX airfoils (i.e. the lift coefficient at the design angle of attack)?
Physics
1 answer:
Alik [6]3 years ago
5 0

Answer:

An investigation is made to determine the performance of simple thin airfoils in the slightly supersonic flow region with the aid of the nonlinear transonic theory first developed by von Kármán[1]. Expressions for the pressure coefficient across an oblique shock and a Prandtl-Meyer expansion are developed in terms of a transonic similarity parameter. Aerodynamic coefficients are calculated in similarity form for the flat plate and asymmetric wedge airfoils, and curves are plotted. Sample curves for a flat plate and a specific asymmetric wedge are plotted on the usual coordinate grid of Cl, Cd,andCmc/4versus angle of attack and Cl versus Mach Number to illustrate the apparent features of nonlinear flow.

Explanation:

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State of motion is described by
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positions of motion is the answer as moving is a motion

3 0
1 year ago
Which piece of evidence did Alfred Wegener use to develop the theory of continental drift?
Eduardwww [97]
The right answer for the question that is being asked and shown above is that: "A.tectonic activity concentrated in certain areas." A piece of evidence did Alfred Wegener use to develop the theory of continental drift is that <span>A.tectonic activity concentrated in certain areas</span>
3 0
3 years ago
A. An automobile mass is 3.5 x103 kg. If the forward thrust (Fnet)
katrin [286]

Answer:

a = 0.8 m/s^2

Explanation:

Force equation: F = ma

F = ma -> a = F/m = 2.8*10^3 N / 3.5*10^3 kg = 0.8 m/s^2

8 0
3 years ago
Atoms are known to form charges due to their ability to gain and lose electrons in reactions. As a result, atoms
galben [10]

Answer:

C. Fe: 24 electrons

Explanation:

From the analogy given, the atom with a charge of +2 is Fe having 24 electrons.

To calculate the charges on an atom;

     Number of charges = Number of protons - Number of electrons.

   O: 10 electrons: 8 protons = 8 - 10 = -2

   N: 10 electrons; 7 protons = 7 - 10 = -3

   Cl: 18 electrons; 17 protons = 17 - 18 = -1

So;

    Fe: 24 electrons and 26 protons = 26 -24  = +2

Therefore, the solution is Fe

7 0
2 years ago
A solenoid that is 78.8 cm long has a cross-sectional area of 15.9 cm2. There are 914 turns of wire carrying a current of 8.25 A
Harlamova29_29 [7]

Answer:

(a) Energy density will be equal to 57.31J/m^3

(b) Total energy will be equal to 0.0718 J

Explanation:

It is given that length of solenoid l = 78.8 cm = 0.788 m

Cross sectional area A=15.9cm^2=15.9\times 10^{-4}m^2

Number of turns of the wire N = 914

Current in the solenoid i = 8.25 A

Inductance of the wire is equal to L=\frac{\mu _0N^2A}{l}=\frac{4\pi \times 10^{-7}\times 914^2\times 15.9\times 10^{-4}}{0.788}=2.117\times 10^{-3}H

(b) Total energy stored in magnetic field U=\frac{1}{2}Li^2=\frac{1}{2}\times 2.11\times 10^{-3}\times 8.25^2=0.0718J

(a) Energy density will be equal to

U_b=\frac{0.0718}{15.9\times 10^{-4}\times 0.788}=57.31J/m^3

7 0
2 years ago
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