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mezya [45]
3 years ago
12

A boat heads north at 30 mph while a steamer heads east at 40 mph at the same time. When is the distance between them 50 mi? Ans

wer:A boat heads north at 30 mph while a steamer heads east at 40 mph at the same time. When is the distance between them 50 mi? Answer:
Physics
1 answer:
Reil [10]3 years ago
7 0

Answer:

1 hour

Explanation:

Speed of the first boat = 30 mph

Speed of the second = 40 mph

The boats will cover different distances but the time taken will be the same.

Time taken by the boats = t

Distance = Speed × Time

Distance covered by the first boat = 30t

Distance covered by the second boat = 40t

Distance between the boats = 50 mi

From the Pythagoras theorem

\sqrt{(30t)^2+(40t)^2}=50\\\Rightarrow \sqrt{2500t^2}=50\\\Rightarrow 50t=50\\\Rightarrow t=\frac{50}{50}=1\ hour

Time taken by the boats when they are 50 mi away is 1 hour

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vlada-n [284]
Given:
1st run: 20 meters North
2nd run: 15 meters East
time: 15 seconds

Average speed = total distance covered / total time taken
Ave. Speed = (20m + 15m) / 15s
Ave. Speed = 35m / 15s
Ave. Speed = 2 1/3  meters per second
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2 years ago
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Answer:

266.66 m/s

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2 years ago
When light moves from air to glass, part of the light is reflected and part of it is refracted. In the image, which ray shows re
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You have not provided the diagram, therefore, I cannot provide an exact answer.
However, I will try to help by explaining how to solve this problem.

When light moves from air to glass:
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In a diagram, the reflected ray would be the one getting back into air while the refracted ray would be the one entering the water.

You can check the attached diagram for further illustrations.

Hope this helps :)

6 0
2 years ago
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3 years ago
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A jeweler working with a heated 47 g gold ring must lower the ring's temperature to make it safe to handle. If the ring is initi
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Mass of gold m₁ = 47 g

Initial temperature of gold T₁ = 99 C

Specific heat of gold C₁ = 0.129 J/gC

final temperature T₂ = 38 C

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m₂ = 6.8 g

6 0
2 years ago
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