Refer to the attached figure. Xp may not be between the particles but the reasoning is the same nonetheless.
At xp the electric field is the sum of both electric fields, remember that at a coordinate x for a particle placed at x' we have the electric field of a point charge (all of this on the x-axis of course):

Now At xp we have:


Which is a second order equation, using the quadratic formula to solve for xp would give us:

or

Plug the relevant values to get both answers.
Now, let's comment on which of those answers is the right answer. It happens that
BOTH are correct. This is simply explained by considring the following.
Let's place a possitive test charge on the system This charge feels a repulsive force due to q1 but an attractive force due to q2, if we place the charge somewhere to the left of q2 the attractive force of q2 will cancel the repulsive force of q1, this translates to a zero electric field at this x coordinate. The same could happen if we place the test charge at some point to the right of q1, hence we can have two possible locations in which the electric field is zero. The second image shows two possible locations for xp.
Answer:
350 miles
Explanation:
When the car starts 2 hours later, the train would have a head start of
50 * 2 = 100 miles
The speed of the car relative to the train is
70 - 50 = 20 mi/hr
For the car to catch up with the train, it must cover the 100 miles difference at the rate of 20mi/hr. So the time it would need to cover this difference is
100 / 20 = 5 hours
After 5 hours, the car would have traveled a distance of
5 * 70 = 350 miles which is also the distance from the station to where the car catches up
9 is D I believe, I don't know about 10
A because it some type of friction
Answer:
acceleration = 0.2625 m/s²
Explanation:
acceleration = ( final velocity - initial velocity ) / time
Here the final velocity is 10.6 m/s and initial velocity is 6.4 m/s and time is 16 s.
using the equation:
acceleration = ( 10.6 - 6.4 ) / 16
= 0.2625 m/s²