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IgorC [24]
3 years ago
6

If a solution has concentration of 1.8 M, how many moles are dissolved in 2.5 L of the solution?

Chemistry
1 answer:
mash [69]3 years ago
7 0

Explanation is in the file

tinyurl.com/wpazsebu

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Bromine has two isotopes: 50.69% of Bromine has a mass number of 79 while 49.31% of Bromine has a mass number of 81. Calculate t
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What is the total mass of three gold bars that weigh 5543 mg, 23.45 mg, and 697.4 mg?
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The total mass is the sum of the masses.
It is
5543 + 23.45 + 697.4 mg =  6263.85 mg

Answer:  6263.85 mg
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3 years ago
Explain what happens to the energy in a wave when a sound is louder.
liraira [26]
Greater amplitude waves have more energy and greater intensity, so they sound louder. ... The same amount of energy is spread over a greater area, so the intensity and loudness of the sound is less. This explains why even loud sounds fade away as you move farther from the source.
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3 years ago
Use a Punnett square to predict the cross of a homozygous tall parent with a homozygous short parent, if tall is dominant over s
ycow [4]

Answer:

All offspring are tall when a homozygous tall parent with homozygous short parent.

Explanation:

When we crossed  homozygous tall parent with homozygous short parent, we conclude that all offspring are tall, because homozygous short parent are supressed under the homozygous tall parent, due to law of dominance.

Law of dominance states that, recessive alleles are suppressed by dominant alleles but they can appear in F2 generation.

Using a punett square, we can predict the cross between homozygous tall and homozygous short parent.      

  The phenotypes are: All are tall plants (4:0).

5 0
3 years ago
Draw the alkane formed when 4,5,5-trimethyl-1-hexyne is treated with two equivalents of hbr.
AveGali [126]
<h3>Answer:</h3>

             The Alkane formed is 5,5-dibromo-2,2,3-trimethylhexane. as shown below in attached scheme (Green Color).

<h3>Explanation:</h3>

                        Alkynes like Alkenes undergo <em>Electrophillic Addition Reactions</em>. The reaction given is a two step reaction. In step 1, the Alkyne adds first equivalent of HBr obeying <em>Markovnikov's rule</em> (i.e. Bromine will add to carbon containing less number of hydrogen atoms) and forms <em>2-bromo-4,5,5-trimethylhex-1-ene</em>. In step 2, the alkene formed in first step (2-bromo-4,5,5-trimethylhex-1-ene) undergoes addition reaction with the second equivalent of HBr via Markovnikov's rule to produce <em>5,5-dibromo-2,2,3-trimethylhexane</em>.

The scheme is attached below, Blue color is assigned to starting Alkyne, Red color is assigned to intermediate Alkene and Green color is assigned to product Alkane respectively.

3 0
4 years ago
Read 2 more answers
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