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Lubov Fominskaja [6]
3 years ago
12

Si en un planeta la presión atmosférica es mayor que 5,1 atm terrestres, los habitantes podrían nadar en ríos de dióxido de carb

ono líquido?
Chemistry
1 answer:
Sphinxa [80]3 years ago
5 0

Answer:

Los habitantes del planeta con una atmósfera superior a 5,1 atm de la Tierra, no estarían nadando en ríos de dióxido de carbono líquido

Explanation:

De las tablas de datos termodinámicos, la presión a la que el vapor de dióxido de carbono está en equilibrio con su estado líquido a una temperatura ambiente de 25 ° C es 6,401 kPa, lo que equivale a 63,17296 atm.

Por lo tanto, a una presión de 5.1 de la atmósfera terrestre, el dióxido de carbono es completamente gaseoso y los habitantes del planeta con una presión atmosférica de 5.1 atm de la Tierra todavía observarían solo hidrógeno gaseoso y no estarían nadando en ríos de dióxido de carbono líquido.

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What atom has 8 protons and 10 electrons?
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Answer:

In your case, you have 8 protons and 10 electrons. This means that the atom will carry a total 2 xx (1-) = 2- net charge. Therefore, you are dealing with an anion that carries a 2- net charge, i.e. it has two more electrons than it does protons.

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What can you say about the strength of the intermolecular forces in neon and argon based on the critical points of Ne and Ar? (c
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Explanation:

Since, it is given that critical temperature of Argon is 150.9 K and critical pressure of Argon is 48.0 atm.

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Which element is one of the most abundant in both solid parts of earth and in living matter?.
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What type of reaction is this?
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3 years ago
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4NH3(g) + 5O2(g) 4NO(g) + 6H2O(g)
Crazy boy [7]

1. The volume of ammonia consumed in the reaction is 23.2 L

2. The volume of oxygen consumed in the reaction is 29 L

<h3>Balanced equation</h3>

4NH₃(g) + 5O₂(g) --> 4NO(g) + 6H₂O(g)

From the balanced equation above,

6 L of H₂O were produced from 4 L of NH₃ and 5 L of O₂

<h3>1. How to determine the volume of ammonia, NH₃ consumed</h3>

From the balanced equation above,

6 L of H₂O were produced from 4 L of NH₃

Therefore,

34.8 L of H₂O will be produced from = (34.8 × 4) / 6 = 23.2 L of NH₃

Thus, 23.2 L of NH₃ were consumed

<h3>2. How to determine the volume of oxygen, O₂ consumed</h3>

From the balanced equation above,

6 L of H₂O were produced from 5 L of O₂

Therefore,

34.8 L of H₂O will be produced from = (34.8 × 5) / 6 = 29 L of O₂

Thus, 29 L of O₂ were consumed

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

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1 year ago
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