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Zepler [3.9K]
3 years ago
11

Ph of a solution is lowered from 7 to 0.2 which acid or base id responsible for this change

Chemistry
1 answer:
Mazyrski [523]3 years ago
7 0

Answer:

....

Explanation:

.................................

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Consider the following reaction at 298K.
dmitriy555 [2]

Answer:

Eªcell > 0; n = 2

Explanation:

The reaction:

I2 (s) + Pb (s) → 2 I- (aq) + Pb2+ (aq)

Is product favored.

A reaction that is product favored has ΔG < 0 (Spontaneous)

K > 1 (Because concentration of products is >>>> concentration reactants).

Eªcell > 0 Because reaction is spontaneous.

And n = 2 electrons because Pb(s) is oxidizing to Pb2+ and I₂ is reducing to I⁻ (2 electrons). Statements that are true are:

<h3>Eªcell > 0; n = 2</h3>
8 0
3 years ago
Which of the following is NOT a representative particle?<br><br> molecule<br> atom<br> electron
kodGreya [7K]
Answer: Molecule


Step-by-step-explanation
3 0
3 years ago
Molecular mass expressed in gram is called<br>​
Elan Coil [88]

Answer:

gram atomic mass

Explanation:

Mass of an atom expressed in grams is known as gram atomic mass. It is equal to the relative atomic mass or atomic weight in grams.

3 0
3 years ago
When KCl dissolves in water:
34kurt

This dissociation occur because:

O had to bond with H due to the Hydrogen bonding rule, which will form OH~ (Hydroxide).

K is more attracted to Hydroxide than Cl, so it will depart Cl and bond with OH~.

that leaves a H and a Cl, which one has a positive charge and the other has a negative, so they will bond and form Hydrochloric Acid.

3 0
3 years ago
For a particular reaction, Δ H ∘ = 55.4 kJ ΔH∘=55.4 kJ and Δ S ∘ = 94.1 J/K. ΔS∘=94.1 J/K. Assuming these values change very lit
nadezda [96]

Answer:

The temperature at which the reaction changes from non-spontaneous to spontaneous is 588.735 K

Explanation:

The spontaneity of a reaction is determined by the change in Gibbs Free Energy, \Delta G^{0}.

\Delta G^{0} =\Delta H^{0} -T\Delta S^{0}

If \Delta G^{0} is greater than zero, then a reaction is feasible.

If \Delta G^{0} is less than zero, then a reaction is not feasible.

To determine the temperature at which the reaction changes from non-spontaneous to spontaneous, we should equate the \Delta G^{0} to zero.

We take \Delta G^{0}=0 as the limiting condition.

T=\frac{\Delta H^{0}}{\Delta S^{0}}=\frac{55.4\times10^{3}}{94.1}=588.735K

Therefore, the temperature is: 588.735K

7 0
4 years ago
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