If you use the next formula with the data given in the exercise you are asking:
Ey[3.4] - F[1.7] = 0
<span>Ey = F/2
</span>and after that what you need to do is sum the moments of the handle about D to zero asumming it is a positive moment and we proceed like this
Ey[1.5sin19] – P[21 – 1.5sin19] = 0
<span>(F/2)[1.5sin19] = P[21 – 1.5sin19] </span>
<span>F = 2P[21 – 1.5sin19] / [1.5sin19] </span>
<span>F = 84P </span>
Answer:
F' = 251.2 lb
Explanation:
It is given that,
The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car’s speed and inversely as the radius of the curve. So,
W is the weight
v is the speed
r is the radius of curve
W is constant, So
If F = 126 lb, v = 25 mph and r = 400 ft
F' = ?, v' = 45 mph and r' = 650 ft
On solving above equation,
F' = 251.2 lb
So, 251.2 lb of force would keep the same car going 45 mph from skidding on a curve of radius 650 ft. Hence, this is the required solution.
Answer and Explanation:
We know by Newton's second law of motion that Force can be given by the rate of change of momentum i.e.,
F = m
where, p is momentum
Now, when EM wave falls on perfectly reflecting body , change in momentum is : -(p+p) = -2p
i.e., after reflection momentum is twice of its initial value
In case of absorption of radiation of EM wave as in perfectly black painted body, change in momentum is half of that in reflection i.e., '-p'
Since, the force, F is equal to the change in momentum, the Force erxerted by the wave will also be half i.e., or 0.5F
Answer:
It can be seen by the eye
Explanation:
Took the test
Answer:
1088 m
Explanation:
3.00 seconds times by 340 =1020+68=1088