Answer:
1088 m
Explanation:
3.00 seconds times by 340 =1020+68=1088
100,200J of heat is required to convert 0.3kg of ice of 0°C to water at same temperature.
Heat = mass * lf
Latent heat of fusion (lf) of water is 334J/g
Heat = 300g * 334 J/g
Heat = 100,200J of heat
I think that it is 80%
Energy. They need energy.
Bromine-2.8 high
Chlorine-3.0 high
Potassium-0.8 low
Lithium-1.0 low
