Answer:
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Explanation:
Explanation:
One way of classifying stars is by their temperature .
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Science strives to be able to describe how stars and planets form and evolve. This requires theories to describe the processes which include:
Star and planet formation
Star and planet composition
Stellar and solar system evolution
The nuclear processes happening inside stars
The scientific method means that all theories are put to the test. By measuring or calculating the temperature, age and composition of other planets and stars the theories can be tested. If observed values of these parameters are not predicted by theories, then the theories are wrong and need to be revised or replaced.
After x seconds, an object will fall
![\frac{1}{2}at^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dat%5E2)
where a is acceleration due to gravity and t is time
so when t=3.3
the distance it will fall is
![(\frac{1}{2})(9.8\frac{m}{s^2})(3.3m)^2](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B2%7D%29%289.8%5Cfrac%7Bm%7D%7Bs%5E2%7D%29%283.3m%29%5E2)
=53.361m
it will fal 53.361 meters
Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion.Displacement<span> is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.
</span>To calculate displacement<span>, simply draw a vector from your starting point to your final position and solve for the length of this line. If your starting and ending position are the same, like your circular 5K route, then your </span>displacement<span> is 0. In physics, </span>displacement<span> is represented by Δs.
For me to solve this I would need to know the time, but I can give you a handy displacement calculator I used that helped me.
https://www.easycalculation.com/physics/classical-physics/constant-acc-displacement.php
Hope I helped.
</span>
The age of the galaxy when we look back is 13.97 billion years.
The given parameters:
- <em>distance of the galaxy, x = 2,000 Mpc</em>
According Hubble's law the age of the universe is calculated as follows;
v = H₀x
where;
H₀ = 70 km/s/Mpc
![T = \frac{x}{V} \\\\T = \frac{x}{xH_0} \\\\T = \frac{1}{H_0} \\\\T = \frac{1}{70 \ km/s/Mpc} \\\\T = \frac{1 \ sec}{70 \times 3.24 \times 10^{-20} } \\\\T = 4.41 \times 10^{17} \ sec\\\\T = \frac{4.41 \times 10^{17} \ sec\ \times \ years}{3600 \ s \ \times\ 24\ h\ \times \ 365.25 \ days} \\\\T = 1.397 \times 10^{10} \ years\\\\T = 13.97 \ billion \ years](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7Bx%7D%7BV%7D%20%5C%5C%5C%5CT%20%3D%20%5Cfrac%7Bx%7D%7BxH_0%7D%20%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B1%7D%7BH_0%7D%20%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B1%7D%7B70%20%5C%20km%2Fs%2FMpc%7D%20%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B1%20%5C%20sec%7D%7B70%20%5Ctimes%203.24%20%5Ctimes%2010%5E%7B-20%7D%20%7D%20%5C%5C%5C%5CT%20%3D%204.41%20%5Ctimes%2010%5E%7B17%7D%20%5C%20sec%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B4.41%20%5Ctimes%2010%5E%7B17%7D%20%5C%20sec%5C%20%20%5Ctimes%20%5C%20years%7D%7B3600%20%5C%20s%20%5C%20%5Ctimes%5C%20%2024%5C%20h%5C%20%20%5Ctimes%20%5C%20365.25%20%5C%20days%7D%20%5C%5C%5C%5CT%20%3D%201.397%20%20%5Ctimes%2010%5E%7B10%7D%20%5C%20years%5C%5C%5C%5CT%20%3D%2013.97%20%5C%20billion%20%5C%20years)
Thus, the age of the galaxy when we look back is 13.97 billion years.
Learn more about Hubble's law here: brainly.com/question/19819028