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Anit [1.1K]
3 years ago
10

If an object emits or reflects light, A. it has a smooth surface. B. it can be seen by the eye. C. it must be the color white. D

. it cannot be a gas.
Physics
2 answers:
kirill [66]3 years ago
5 0

Answer:

It can be seen by the eye

Explanation:

Took the test

V125BC [204]3 years ago
5 0

Answer:

D. It can be seen by eye

Explanation:

I just got it right.

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An RC circuit takes t = 2.5 ms to charge to 35% of its full charge after it weas connected to a battery, What is the total time
marin [14]

Answer: time taken to charge to 95%

t = -5.80[ln(1-0.95)]

t = 17.38ms

Explanation:

For an RC Charging circuit

Where Vs

Vc = Vs (1 - e^(-t/RC))

Vc/Vs = 1 - e^(-t/RC)

-t/RC = ln(1 - Vc/Vs)

t = -RC[ln(1 - Vc/Vs)] and RC = k = -t/ln(1 - Vc/Vs)

Where ;

Vc = voltage across the capacitor

Vs = voltage supply

t = charging time = 2.5ms

k = RC = time constant.

Vc/Vs = 0.35

To calculate the time constant k;

k = -t/ln(1- Vc/Vs)

k = -2.5/ln(1-0.35)

k = 5.80ms

time taken to charge to 95%

t = -5.80[ln(1-0.95)]

t = 17.38ms

4 0
3 years ago
There are six books in a stack, and each book weighs 5 N. The coefficient of static friction between the books is 0.2. With what
NikAS [45]

Answer:

b. 5 N

Explanation:

Each book weighs 5 N.  Therefore, five books weigh 25 N.  The friction force is:

Ff = Fn μ

Ff = (25 N) (0.2)

Ff = 5 N

3 0
3 years ago
Read 2 more answers
Please Help!
loris [4]
There is a net force of 15N in The direction of Levi
6 0
3 years ago
Read 2 more answers
How much would it cost to operate five incandescent light bulbs for the months of April and May, collectively, given that each b
const2013 [10]

Answer:

Total Cost is 41.18 AED

Explanation:

Per day number of hours light bulbs were on=3hours

5 bulbs power consumption = 150Wx5 = 750W

Electricity usage per day = 750 x 3 = 2250Wh = 2.25kWh

April has 30 days and May has 31 days. Therefore totals days = 61days

Total power consumption = 2.25x 61 = 137.25kWh

Total Cost = 137.25x 0.30 = 41.175 AED

3 0
3 years ago
An old manuscript reveals that a landowner in the time of King Arthur held 3.00 acres of plowed land plus a livestock area of 25
iragen [17]

Answer:

(a) Total area is 14.5 roods

(b) Total area is 14674.522 square meters

Explanation:

Area occupied by land = 3 acres

1 acre = 40 perches by 4 perches = 160 square perches

3 acres = 3×160 = 480 square perches

Area occupied by livestock = 25 perches by 4 perches = 100 square perches

Total area = 480 + 100 = 580 square perches

1 rood = 4 perches by 1 perch = 4 square perches

580 square perches = 580/4 = 14.5 roods

(b) Total area = 580 square perches

1 perch = 16.5ft = 16.5/3.2808 = 5.03 meters

580 square perches × (5.03 meters/1 perch)^2 = 580 ×25.3009 square meters = 14674.522 square meters

8 0
3 years ago
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