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jekas [21]
3 years ago
12

4. All electromagnetic radiation moves at the speed of ________________, which is _________________ m/s.

Physics
1 answer:
VARVARA [1.3K]3 years ago
7 0

Answer:

All electromagnetic radiation, regardless of its wavelength, travels at what is called the "speed of light". In a vacuum, it is measured as 299,792,458 meters per second. 3.0 x 108 meters per second.

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4. The value of the before and after-collision momentum of two colliding objects is shown in the
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Answer:A) WHICH is 0kgm/s

Explanation:

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Which statement is true regarding the vectors shown.
kap26 [50]

Answer:

Y-> + F-> +G ->=E->

Explanation:

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Please help me answer the following question!
Troyanec [42]

Answer:

P = 0

Explanation:

Momentum is defined as the quentity of motion contained in a body. Mathematically, it can be defined as the product of mass and velocity. So, in order to determine the Volkswagen Beetle, at rest, we can use the simple formula, as follows:

where,

P = Momentum of Volkswagen Beetle = ?

m = Mass of Volkswagen Beetle = 750 kg

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3 0
2 years ago
A small sphere with mass mcarries a positive chargeqand is attached to one end of a silk fiber of lengthL. The other end of the
Aleksandr-060686 [28]

Answer:

(a):  The magnitude of the electric force on the small sphere = \dfrac{q\sigma}{2\epsilon_o}.

(b): Shown below.

Explanation:

<u>Given:</u>

  • m = mass of the small sphere.
  • q = charge on the small sphere.
  • L = length of the silk fiber.
  • \sigma = surface charge density of the large vertical insulating sheet.

<h2>(a):</h2>

When the dimensions of the sheet is much larger than the distance between the charge and the sheet, then, according to Gauss' law of electrostatics, the electric field experienced by the particle due to the sheet is given as:

\rm E = \dfrac{\sigma}{2\epsilon_o}.

<em>where,</em>

\epsilon_o is the electrical permittivity of the free space.

The electric field at a point is defined as the amount of electric force experienced by a unit positive test charge, placed at that point. The magnitude electric field at a point and the magnitude of the electric force on a charge q placed at that point are related as:

\rm F_e=qE.

Thus, the magnitude of the electric force on the small sphere is given by

\rm F_e = q\times \dfrac{\sigma }{2\epsilon_o}=\dfrac{q\sigma}{2\epsilon_o}.

The sheet and the small sphere both are positively charged, therefore, the electric force between these two is repulsive, which means, the direction of the electric force on the sphere is away from the sheet along the line which is perepndicular to the sheet and joining the sphere.

<h2>(b):</h2>

When the sphere is in equilibrium, the tension in the fiber is given by the resultant of the weight of the sphere and the electric force experienced by it as shown in the figure attached below.

According to the fig.,

\rm \tan \theta = \dfrac{F_e}{W}.

<em>where,</em>

  • \rm F_e = electric force on the sphere, acting along left.
  • \rm W = weight of the sphere, acting vertically downwards.

<em />

\rm F_e = \dfrac{q\sigma}{2\epsilon_o}\\\\W=mg\\\\Therefore,\\\\\tan\theta = \dfrac{\dfrac{q\sigma}{2\epsilon_o}}{mg}=\dfrac{q\sigma}{2mg\epsilon_o}.\\\Rightarrow \theta=\tan^{-1}\left ( \dfrac{q\sigma}{2mg\epsilon_o}\right ) .

g is the acceleration due to gravity.

6 0
3 years ago
A fox fleeing from a hunter encounters a 0.700 m tall fence and attempts to jump it. The fox jumps with an initial velocity of 7.
iris [78.8K]

Answer:0.61 m

Explanation:

Given

Initial velocity (u)=7.40 m/s

launch angle \theta =45^{\circ}

height of fence=0.7 m

Trajectory of Projectile is given by

y=x\tan \theta -\frac{gx^2}{2u^2\cos^2\theta }

For x=2.1 m  

y=2.1\tan (45)-\frac{9.8\times 2.1^2}{2\times 7.4^2\times (\cos 45)^2}

y=2.1-0.789

y=1.31 m

At x=2.1 m Y=1.31

therefore Fox clear fence by a margin =1.31-0.7=0.61 m

7 0
3 years ago
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