Answer: if the pressure in the container is doubled, then the temperature will double too.
Justification:
You can rely on Gay-Lussac's law for ideal gases to answer the question.
According to that law, the pressure and temperature of a fixed amount of gas in a closed rigid container (constant volume) varie in direct proportion.
Mathematically, you can write in this way:
P/T = k
P₁ / T₁ = P₂ / T₂
That means, that if the pressure in the container is doubled, then the temperature will double too.
You can see that mathematically:
P₂ = 2 P₁
T₂ = (T₁ / P₁)(P₂) = (T₁ / P₁) (2 P₁) = 2 T₁
Let v = the running speed
After running at constant speed for 26 min, the distance traveled is
d = (v m/min)*(26 min) = 26v m
Because there are 1500 m to go, the distance traveled is
10000 - 1500 = 8500 m
The running speed is
v = (8500 m)/(26 min) = 326.9 m/min
In km/h, the speed is
v = (0.3269 km/min)*(60 min/h) = 19.6 km/h
Answer: The running speed is 19.6 km/h
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Find Acceleration
Now
Using 1st equation of kinematics
Answer:
Explanation:
It is given that,
Mass of the loop, m = 10 g = 0.01 kg
Resistance of the loop, R = 0.02 ohms
Dimension of square loop, 7 cm × 7 cm
Area of the loop,
At time t = 0 s, the magnetic field increases from 0 to 1 T in 0.01 s
(a) Due to change in magnetic field, an emf is induced in the loop. Using the formula for induced emf as :
Now using Ohm's law to find the induced current in the loop. It is given by :
I =24.5 A
(b) A magnetic force acting on the loop is given by :
F = 0.8575
Since,
v = 0.8575 m/s
Hence, this is the require solution.