A student throws a rock horizontally from the edge of a cliff that is 20 m high. The rock has an initial speed of 10 m/s. If air
1 answer:
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Answer:
a)
b)
Explanation:
From the question we are told that
Speed of opposing player
First player chase his opponent after
Acceleration of first player
Let time of catch be
a)Generally the Equation for distance covered is mathematically given as follows
Distance to catch First opponent
Distance to covered Second opponent
Generally when first opponent catch the second opponent it is represented mathematically as
b)Generally the the total time traveled by the first opponent is mathematically given as
Answer:
its potential energy decreases and its electric potential decreases.
Explanation:
Let's consider a radial field for simplicity. We have:
- The electric potential of the field is given by:
where
k is the Coulomb's constant
Q is the charge source of the field
r is the distance from Q
We see that the electric potential decreases as we move away from the source. If we consider a positive charge q moving in the direction of the electric field, this charge q will move away from the charge Q (because the field lines generated by the positive particle Q point away from the particle), so the electric potential will decrease.
- The potential energy of the moving charge is given by
where q is the magnitude of the charge. As we said previously, V is decreasing while the charge is moving in the direction of the field, so since U is directly proportional to V, U will decrease as well.