Answer:
the longest wavelength of incident sunlight that can eject an electron from the platinum is 233 nm
Explanation:
Given data
Φ = 5.32 eV
to find out
the longest wavelength
solution
we know that
hf = k(maximum) +Ф ...............1
here we consider k(maximum ) will be zero because photon wavelength max when low photon energy
so hf = 0
and hc/ λ = +Ф
so λ = hc/Ф ................2
now put value hc = 1240 ev nm and Φ = 5.32 eV
so hc = 1240 / 5.32
hc = 233 nm
the longest wavelength of incident sunlight that can eject an electron from the platinum is 233 nm
<u> Ohms law: </u> This law relates voltage difference between two points. Mathematically, the law states that V=IR;
Where
V = voltage difference ; in volts
I = Current ; in Amperes
R = Resistance ; in ohms
<u>1. Answer : </u> given that R = 10 ; V= 12 V ; I = ?
From ohms law, I = V/R
= 12/10
= 1.2 Amp.
<u>2. Answer:</u> given that R = 10 ; V= ? ; I = 5
From ohms law, V = IR
= 10×5 = 50 V
<u>3 . Answer:</u> given that R = ? ; V= 120 ; I = 5
From ohms law, R = V/I
= 120/5
= 24 Ω
<u>4 . Answer:</u> given that R = ? ; V= 10 ; I = 20
From ohms law, R = V/I
= 10/20
= 0.5 Ω
<u>5 . Answer:</u> given that R = 480 ; V= 24 ; I = ?
From ohms law, I = V/R
= 24/480
= 0.05 A
<u>6. Answer:</u> given that R = 150 ; V= ? ; I = 1
From ohms law, V = IR
= 1 × 150
= 150 V