Answer:
a) The back spoon gives a right image (upright)
b) the front gives an inverted image
Explanation:
The spoon is a curved metallic object, when we see ourselves from the back we have a convex mirror, in this type of mirror when the law of reflection is applied the rays diverge therefore the eye-brain system forms the image with the prolongation of the rays, therefore the image is straight and smaller than the object.
When we look through the deep side of the spoon, we have a concave mirror and as the object (we) is further away than the distance, the rays converge to a point, so the image is real, inverted smaller than the object.
In summary.
a) The back spoon gives a right image (upright)
b) the front gives an inverted image
I would make a flying car
Any type of wetland that has been developed or maintained by humans for uses such as aquaculture, irrigation, or water storage.
<h3>What is a human-made wetland ?</h3>
Any kind of wetland that has been created or kept up by people for purposes like water storage, irrigation, or aquaculture.
In India's Punjab state, in the Kapurthala district, lies the man-made Kanji Wetland, which includes the Kanji Lake.
In order to give irrigation facilities to the hinterland, it was built by building the headworks over the perennial Bien River, a tributary of the Beas River.
The Sunderbans are India's biggest wetland. The world's biggest mangrove forest includes Sunderban Wetland.
Hence, the human-made wetland is an artificial wetland.
To learn more about the human-made wetland refer;
brainly.com/question/1334452
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To solve this problem, we will start by defining each of the variables given and proceed to find the modulus of elasticity of the object. We will calculate the deformation per unit of elastic volume and finally we will calculate the net energy of the system. Let's start defining the variables
Yield Strength of the metal specimen
Yield Strain of the Specimen
Diameter of the test-specimen
Gage length of the Specimen
Modulus of elasticity
Strain energy per unit volume at the elastic limit is
Considering that the net strain energy of the sample is
Therefore the net strain energy of the sample is 
