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kvasek [131]
3 years ago
11

What solid figure is shown below? triangular pyramid square pyramid rectangular prism cylinder

Mathematics
2 answers:
Gennadij [26K]3 years ago
5 0

RECTANGULAR PRISMS

also known as cuboids ....are all around us. A few of the examples are books, boxes, buildings, bricks, boards, doors, containers, cabinets, mobiles, and laptops.

:-)

denpristay [2]3 years ago
5 0

the answer is rectangular prism

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For the function f(x)=3xsquared- 2x+5 find f(1) f(-2) and f(a)
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f(x)=3x^2-2x+5\\\\
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f(1)=3*1^2-2*1+5=3-2+5=\textbf{6}\\\\
f(-2)\ \ Substitude\ x=-2\\
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4 years ago
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Answer:

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7 0
3 years ago
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Identify whether the series sigma notation infinity i=1 15(4)^i-1 is a convergent or divergent geometric series and find the sum
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Answer:  The correct option is

(d) This is a divergent geometric series. The sum cannot be found.

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S=\sum_{i=1}^{\infty}15(4)^{i-1}.

We are to identify whether the given geometric series is convergent or divergent. If convergent, we are to find the sum of the series.

We have the D' Alembert's ratio test, states as follows:

Let, \sum_{i=1}^{\infty}a_i is an infinite series, with complex coefficients a_i and we consider the following limit:

L=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}.

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For the given series, we have

a_i=15(4)^{i-1},\\\\a_{i+1}=15(4)^i.

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L\\\\\\=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i-1}}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i}4^{-1}}\\\\\\=\dfrac{1}{4^{-1}}\\\\=4>1.

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Thuds, (d) is the correct option.

7 0
4 years ago
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