Answer:
Height = 53.361 m
Explanation:
There are two balloons being thrown down, one with initial speed (u1) = 0 and the other with initial speed (u2) = 43.12
From the given information we make the following summary
= 0m/s
= t
= 43.12m/s
= (t-2.2)s
The distance by the first balloon is
where
a = 9.8m/s2
Inputting the values
The distance traveled by the second balloon
Inputting the values
simplifying
Substituting D of the first balloon into the D of the second balloon and solving
Now we know the value of t. We input this into the equation of the first balloon the to get height of the apartment
Answer:
markers are 29.76 m far apart in the laboratory
Explanation:
Given the data in the question;
speed of particle = 0.624c
lifetime = 159 ns = 1.59 × 10⁻⁷ s
we know that; c is speed of light which is equal to 3 × 10⁸ m/s
we know that
distance = vt
or s = ut
so we substitute
distance = 0.624c × 1.59 × 10⁻⁷ s
distance = 0.624(3 × 10⁸ m/s) × 1.59 × 10⁻⁷ s
distance = 1.872 × 10⁸ m/s × 1.59 × 10⁻⁷ s
distance = 29.76 m
Therefore, markers are 29.76 m far apart in the laboratory
C. is the correct response.
Answer:
Acceleration of the bullet while moving into the clay is -312500 ms⁻²
Explanation:
Given data
Initial velocity (v₁) = 250 m/s Final velocity (v₂) = 0 m/s
Distance (s)= 0.1 m acceleration (a) = ?
Using 3rd equation of motion
2as = v₂²- v₁²
2 × a × 0.1 = 0² - 250²
0.2 × a = -62500
a = -62500/0.2
a = -312500 m/s²
Here negative sign indicate that bullet slow down and it is deceleration i.e negative acceleration.
