All categories

2 years ago

Barry slides across an icy pond. The coefficient of kinetic friction between his

Physics

1 answer:

Soloha48 [4]2 years ago

4 0

The force of friction acting on him is 122 N. The correct answer is option C

<h3>What is Friction ?</h3>

Friction is a force that opposes the motion of a static or a moving object.

Given that Barry slides across an icy pond. The coefficient of kinetic friction between his shoes and the ice is 0.15. If his mass is 83 kg

The given parameters are;

Mass m = 83 kg

Coefficient of kinetic friction μ = 0.15

Frictional force $F_{r}$ = ?

The normal reaction N on the body = mg

N = 83 x 9.8

N = 813.4 N

The Frictional force formula is $F_{r}$ = μN

$F_{r}$ = 0.15 x 813.4

$F_{r}$ = 122.01 N

Therefore, the force of friction acting on him is 122 N approximately.

Learn more about Friction here: brainly.com/question/24338873

#SPJ1

You might be interested in

Which is an example of nuclear energy being converted into heat and light energy?

likoan [24]

The answer to the question is A

6 0

3 years ago

Read 2 more answers

A block of mass m is pushed up against a spring, compressing it a distance x, and the block is then released. The spring project

Gwar [14]

Answer:

$x' = 10 x$

Explanation:

By energy conservation we know that spring energy is converted into kinetic energy of the block

so we will have

$\frac{1}{2}kx^2 = \frac{1}{2}mv^2$

so we will have

$v = \sqrt{\frac{k}{m}}(x)$

now we will have same thing for another mass 4m which moves out with speed 5v

so we have

$5v = \sqrt{\frac{k}{4m}}(x')$

now from above two equations we have

$\frac{5v}{v} = \frac{x'}{2x}$

so we have

$x' = 10 x$

3 0

2 years ago

How many electron shells does an atom of oxygen have? (A.) 1 (B.) 2 (C.) 3 (D.) 4

Vladimir79 [104]

It has two electrons

8 0

3 years ago

Read 2 more answers

What is the reason for the widespread use of fins on surfaces? Group of answer choices Decreasing the rate of heat transfer from

kompoz [17]

Answer:

ask your member

Explanation:

kayo lang din makakasagot nyan

4 0

2 years ago

A 2.8 kg grinding wheel is in the form of a solid cylinder of radius 0.1 m. a) What constant torque will bring it from rest to a

kogti [31]

Answer:

a) τ = 0.672 N m , b) θ = 150 rad , c) W = 100.8 J

Explanation:

a) for this part let's start by finding angular acceleration, when the angular velocity stops it is zero (w = 0)

w = w₀ + α t

α = -w₀ / t

α = 120 / 2.5

α = 48 rad / s²

The moment of inertia of a cylinder is

I = ½ M R²

Let's calculate the torque

τ = I α

τ = ½ M R² α

τ = ½ 2.8 0.1² 48

τ = 0.672 N m

b) we look for the angle by kinematics

θ = w₀ t + ½ α t2

θ = ½ α t²

θ = ½ 48 2.5²

θ = 150 rad

c) work in angular movement

W = τ θ

W = 0.672 150

W = 100.8 J

7 0

2 years ago