Explanation:
Given that,
Capacitor = 30μC
Resistor = 49.0Ω
Voltage = 30.0 V
Frequency = 60.0 Hz
We need to calculate the impedance
Using formula of impedance
.....(I)
We need to calculate the value of 
Using formula of 



Put the value of
into the formula of impedance


(a). We need to calculate the rms current in the circuit
Using formula of rms current



The rms current in the circuit is 0.30 A.
(b). We need to calculate the rms voltage drop across the resistor
Using formula of rms voltage

Put the value into the formula


The rms voltage drop across the resistor is 14.7 V
(c). We need to calculate the rms voltage drop across the capacitor
Using formula of rms voltage



The rms voltage drop across the capacitor is 26.53 V.
Hence, This is the required solution.