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1 year ago

Barry slides across an icy pond. The coefficient of kinetic friction between his

Physics

1 answer:

Soloha48 [4]1 year ago

4 0

The force of friction acting on him is 122 N. The correct answer is option C

<h3>What is Friction ?</h3>

Friction is a force that opposes the motion of a static or a moving object.

Given that Barry slides across an icy pond. The coefficient of kinetic friction between his shoes and the ice is 0.15. If his mass is 83 kg

The given parameters are;

Mass m = 83 kg

Coefficient of kinetic friction μ = 0.15

Frictional force $F_{r}$ = ?

The normal reaction N on the body = mg

N = 83 x 9.8

N = 813.4 N

The Frictional force formula is $F_{r}$ = μN

$F_{r}$ = 0.15 x 813.4

$F_{r}$ = 122.01 N

Therefore, the force of friction acting on him is 122 N approximately.

Learn more about Friction here: brainly.com/question/24338873

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Answer:

1625

Explanation:

Ns/Np = Vs/Vp

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Ns = 2.5 x 650

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2 years ago

Calculate the work against gravity required to build the right circular cone of height 4 m and base of radius 1.2 m out of a lig

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Answer:

Work done = 35467.278 J

Explanation:

Given:

Height of the cone = 4m

radius (r) of the cone = 1.2m

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Now,

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thus,

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if the accuracy in measuring the position of a particle increases, what happens to the accuracy in measuring its velocity?

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The answer to this question should be: The accuracy in measuring its velocity decreases

Hope I helped

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A certain frictionless simple pendulum having a length L and mass M swings with period T. If both L and M are doubled, what is t

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The new period is D) √2 T

$\texttt{ }$

<h3>Further explanation</h3>

Let's recall Elastic Potential Energy and Period of Simple Pendulum formula as follows:

$\boxed{E_p = \frac{1}{2}k x^2}$

where:

<em>Ep = elastic potential energy ( J )</em>

<em>k = spring constant ( N/m )</em>

<em>x = spring extension ( compression ) ( m )</em>

$\texttt{ }$

$\boxed{T = 2\pi \sqrt{ \frac{L}{g} }}$

where:

<em>T = period of simple pendulum ( s )</em>

<em>L = length of pendulum ( m )</em>

<em>g = gravitational acceleration ( m/s² )</em>

Let us now tackle the problem!

$\texttt{ }$

<u>Given:</u>

initial length of pendulum = L₁ = L

initial mass = M₁ = M

final length of pendulum = L₂ = 2L

final mass = M₂ = 2M

initial period = T₁ = T

<u>Asked:</u>

final period = T₂ = ?

<u>Solution:</u>

$T_1 : T_2 = 2\pi \sqrt{ \frac{L_1}{g} }} : 2\pi \sqrt{ \frac{L_2}{g} }}$

$T_1 : T_2 = \sqrt{L_1} : \sqrt{L_2}$

$T : T_2 = \sqrt{L} : \sqrt{2L}$

$T : T_2 = 1 : \sqrt{2}$

$\boxed {T_2 = \sqrt{2}\ T}$

$\texttt{ }$

<h3>Learn more</h3>

Kinetic Energy : brainly.com/question/692781

Acceleration : brainly.com/question/2283922

The Speed of Car : brainly.com/question/568302
Young Modulus : brainly.com/question/9202964
Simple Harmonic Motion : brainly.com/question/12069840

$\texttt{ }$

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Elasticity

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2 years ago

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Making A the subject of the formular

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Explanation:

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